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Charra [1.4K]
3 years ago
5

at 6:00 a.m., the temperature is 58°. At 2:00 p.m., temperature is 76°. Find the rate of change in degrees per hour during this

time.
Mathematics
1 answer:
lesya [120]3 years ago
6 0

Answer:

The rate of change is of 2.25 degrees per hour.

Step-by-step explanation:

The rate of change in degrees per hour is given by by the change in temperature divided by the change in time(by number of hours).

In this question:

From 6 am to 2 pm, there are 12 - 6 + 2 - 0 = 6 + 2 = 8 hours

The change in temperature was of 76 - 58 = 18º

Rate of change:

18º/8 = 2.25º

The rate of change is of 2.25 degrees per hour.

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Step-by-step explanation:

Let's get our relevant base equations listed out:

d = 2r

area = pi*r²

c = πd

Thus, d=2*5m  = 10m, c=π*10m=10π m, and area = 25m²*π

Feel free to ask further questions!

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18 miles is what percent of 24 miles?
Gekata [30.6K]

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4 0
3 years ago
I NEED HELP WITH NUMBER 4​
weeeeeb [17]

Answer:

4.5 inches

Step-by-step explanation:

To find the height in inches of the model, you need to change the ration into a fraction:

\frac{1}{50}

Then try to figure out the value of the denominator in terms of the ratio:

\frac{1}{50} =\frac{x}{725}

In this equation we need to figure out how much the denominator of the fraction is changing by, by dividing 725 by 50. Then, multiply that by one:

4.5

8 0
3 years ago
Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X &gt; 10) b. P(X &gt; 20) c
GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0

The value of E (X) is 10.

The parameter λ is:

\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10

(a)

Compute the value of P (X > 10) as follows:

P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

P(X

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

P(X

Take natural log on both sides.

ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30

Thus, the value of x is 30.

7 0
3 years ago
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