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3 years ago

If f(x)=2(3^x)+1 what is the value of f(2)?

Mathematics

2 answers:

pentagon [3]3 years ago

8 0

Answer:

$f(2)=19$

Step-by-step explanation:

$f(x) =2(3^{x} )+1$

$f(2)= 2(3^{2})+1$

$f(2)= 2(9) +1$

$f(2)= 18+1$

$f(2)=19$

plz mark me brainliest. :)

scoundrel [369]3 years ago

5 0

Answer:

Step-by-step explanation:

F(-2) = 13

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Advocard [28]

Answer:

$\sqrt{99}$

Step-by-step explanation:

you can use the distance formula to find the distance between two given points.

the distance formula is:

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so if you simply plug in you get:

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and again

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3 years ago

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Pavlova-9 [17]

Answer:

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2 years ago

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aalyn [17]

Answer:

Step-by-step explanation:

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3 years ago

how to use Lcd in this problem? [a-2. -_1_ =_3_]find Lcd [ a+3 1 a-2]. (a+3)(a+2). multiply all neumerator to (LCD) a-2 - 1= 3 _

san4es73 [151]

It's not entirely clear to me what you're trying to solve, but it looks like the initial equation is

$\dfrac{a-2}{a+3} -1 = \dfrac3{a+2}$

First convert each term into a fraction with the same (i.e. the least common) denominator. The first term needs to be multiplied by a + 2; the second term by (a + 3) (a + 2); and the third term by a + 3 :

$\dfrac{a-2}{a+3}\cdot\dfrac{a+2}{a+2} -1\cdot\dfrac{(a+3)(a+2)}{(a+3)(a+2)} = \dfrac3{a+2}\cdot\dfrac{a+3}{a+3} \\\\ \dfrac{(a-2)(a+2)}{(a+3)(a+2)} - \dfrac{(a+3)(a+2)}{(a+3)(a+2)} = \dfrac{3(a+3)}{(a+3)(a+2)}$