Answer:
0.6443 = 64.43% of the business travelers will have to stoop
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Each feet is 12 inches
So
5'9'' = 5*12 + 9 = 69
5'10'' = 5*12 + 10 = 70
![\mu = 70, \sigma = 2.7](https://tex.z-dn.net/?f=%5Cmu%20%3D%2070%2C%20%5Csigma%20%3D%202.7)
What percentage of the business travelers will have to stoop?
This is 1 subtracted by the pvalue of Z when X = 69. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{69 - 70}{2.7}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B69%20-%2070%7D%7B2.7%7D)
![Z = -0.37](https://tex.z-dn.net/?f=Z%20%3D%20-0.37)
has a pvalue of 0.3557.
1 - 0.3557 = 0.6443
0.6443 = 64.43% of the business travelers will have to stoop
I believe it would be this:
3 (2×-5)=1+4× 6-15=1+4× 6×=1+4×+15
I hope this answer helped, and my deepest apologies if I have calculated wrongly. Math is tricky! :)
Answer:175
Step-by-step explanation:70/40=1.75
1.75x100=175
Answer:
R = 10 cm
Step-by-step explanation:
The area of a spherical shape is given by :
![A=4\pi r^2](https://tex.z-dn.net/?f=A%3D4%5Cpi%20r%5E2)
Where
r is the radius of the sphere
ATQ,
One large bubble separates into four small bubbles so that the total area of the small bubbles is equal to the area of the large bubble.
The radius of each small bubble is 5 cm
Using the given condition,
![4\pi R^2=4\times (4\pi r^2)\\\\R^2=4r^2\\\\R=\sqrt{4r^2} \\\\R=2r\\\\R=2\times 5\\\\R=10\ cm](https://tex.z-dn.net/?f=4%5Cpi%20R%5E2%3D4%5Ctimes%20%284%5Cpi%20r%5E2%29%5C%5C%5C%5CR%5E2%3D4r%5E2%5C%5C%5C%5CR%3D%5Csqrt%7B4r%5E2%7D%20%5C%5C%5C%5CR%3D2r%5C%5C%5C%5CR%3D2%5Ctimes%205%5C%5C%5C%5CR%3D10%5C%20cm)
So, the radius of the large bubble is equal to 10 cm.
Answer:
b. From 1980 to 1990
Step-by-step explanation:
good luck