3 years ago

Can anyone please help

1 answer:

6 0

Hello,

9)
∠DBC=90-54=36°
∠CAD=∠DBC=36°

10)
∠BOC=1/2(360-2*100)=1/2*160=80°
∠l=1/2∠AOD=1/2∠BOC=40°

11)
JL=10
JA=7==>AL=10-7=3

LC=AL=3
LK=11
CK=11-3=8

KB=KC=8
BJ=JA=7

perimeter=10+11+15=36

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