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Paraphin [41]
3 years ago
12

Please I need your help desperately what is the area of this triangle? See attached image thank you so much

Mathematics
1 answer:
Rama09 [41]3 years ago
7 0

To find the area of the given traingle we have to draw perpendicular from point 'J' which meets the x axis at point (2,0) and let us named it 'P'.

As we know that area of triangle is


[tex] = \frac{1}{2}\times b \times h [\tex]


Here base 'b' will be LK and height 'h' will be JP

Here,

LK= 4 units JP=4 units


Area ={1}{2} *(4)*(4)

On solving the equation we get,

Area=8 Sq units

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Answer:

The interval is (.0817, .118).

Step-by-step explanation:

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<u>1. Conditions</u>

First we must check the conditions.

<em>Randomization condition: </em>The sample is given to be random, so we can assume independence.

<em>Success/failure condition: </em>Both np>10 and nq>10 must be met.

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<em>10% condition: </em>The sample cannot be greater than 10% of the population.

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<u></u>

<u>2. Mechanics</u>

<u>Find </u>\hat{p}<u>, the sample proportion.</u>

103/1030 = .1

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<u>Find z* (z star), the critical z-value.</u>

You can do this on your calculator using 2nd->VARS->3 (or you can memorize it - it's 1.96. Winky face.) This is called the invNorm function, that takes the left side area under the normal curve. But what do we plug in to the invNorm function?

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<u>Plug values into the equation.</u>

\hat{p} ± z*\sqrt{\frac{\hat{p}\hat{q}}{n} }

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.1 - .0183 = .0817

.1 + .0183 = .118

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Based on this sample, we are 95% confident that the proportion of people the company contacts who may buy something is between .0817 and .118. That isn't very likely, but maybe they'll make a little profit!

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