Which of the following describes the transformation from Figure 1 to Figure 2?

Suppose the population standard deviation is σ = 5 , an SRS of n = 100 is obtained, and the confidence level is chosen to be 98%

beks73 [17]

Answer:

1.165.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.98}{2} = 0.01$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.01 = 0.99$ , so $z = 2.33$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

In this problem, we have that:

$\sigma = 5, n = 100$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$M = 2.33*\frac{5}{\sqrt{100}} = 1.165$

So the correct answer is:

1.165.

6 0

4 years ago

I need help for this to pass my last math class please help and show your work

Maksim231197 [3]

-12 + 3x + 2 = 5x - 10 - 8x
-10 + 3x = -3x -10
-10 + 6x = -10
6x = 0
x = 0

3 0

3 years ago

Ningbo Shipping has issued preferred stock at its $125 per share par value. The stock will pay a $15 annual dividend. The cost o

katen-ka-za [31]

Answer:

The cost of Ningbo Shipping Preferred stock is 12.40%

Step-by-step explanation:

In this question, we are asked to calculate the cost of Ningbo shipping Preferred stock.

To calculate this, we make use of the following mathematical relation;

The cost preferred stock Kp = Annual dividends/ Issued price-Cost of Issuing

From the question, we identify the following;

Issued price = $125

Annual dividend = $15

Cost of Issuing = $4

Inserting these into the formula we have;

Kp = $15/$125 - $4 = 12.40%

This means that Cost of Ningbo shipping preferred stock is 12.40%

5 0

3 years ago

Can pls someone help me with my homework

Wewaii [24]

Answer:

is there a formula in the notes if so put it in then it might help out

Step-by-step explanation:

4 0

3 years ago

Required information An article presents a new method for timing traffic signals in heavily traveled intersections. The effectiv

Natasha2012 [34]

Answer:

$652.6-2.01\frac{311.7}{\sqrt{50}}=563.997$

$652.6+2.01\frac{311.7}{\sqrt{50}}=741.203$

So on this case the 95% confidence interval would be given by (563.997;741.203)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=652.6$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=311.7 represent the sample standard deviation

n=50 represent the sample size

Soltuion to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=50-1=49$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,49)".And we see that $t_{\alpha/2}=2.01$

Now we have everything in order to replace into formula (1):

$652.6-2.01\frac{311.7}{\sqrt{50}}=563.997$

$652.6+2.01\frac{311.7}{\sqrt{50}}=741.203$

So on this case the 95% confidence interval would be given by (563.997;741.203)

6 0

3 years ago