What is the diameter of (7/3,-2/3), (2,3/2)

Parallel Lines Cut by a Transversal: Maze

CaHeK987 [17]

Start from Start Here square, the pointer to the next question to resolve is given by the solution to the equation in the current square

The values of the Maze are as follows;

x = 10
x = 8
x = -9
x = 5
x = 11
x = 3
x = -5
x = 9
x = 7
x = -7

Reason:

The solutions are;

10·x + 15 = 12·x - 5 by alternate interior angles theorem

∴ x = 10

6·x + 6 = 5·x + 14 by alternate exterior angles theorem

∴ x = 8

x + 109 = 100 by corresponding angles theorem

∴ x = -9

11·x + 5 + 120° = 180° by same side interior angles theorem

∴ x = 5

11·x - 1 = 10·x + 10 by corresponding angles theorem

∴ x = 11

35·x + 5 = 110 by corresponding angles theorem

∴ x = 3

x + 85 + x + 105 = 180 by same side interior angles theorem

∴ x = -5

7·x - 3 + 12·x + 12 = 180° by same side interior angles theorem

∴ x = 9

19·x - 3 = 130 by alternate interior angles theorem

∴ x = 7

x + 67 = 60 by alternate interior angles theorem

x = -7

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7 0

3 years ago

Dr. Gonzalez is considering joining the Garden Club. If he pays a $25 membership fee, he

ziro4ka [17]

Answer:

In the Garden Club the cost will be a fixed fee of $25 and $10 for each rosebush, so if he buys X rosebushes, the total cost will be:

C1(X) = $25 + $10*X

While in the local nursery there is no initial cost, and each rosebush costs $15, so if he buys X rosebushes, the total cost will be:

C2(X) = $15*X

Now, let's find the value of X where C1 and C2 are equal, this is:

$25 + $10*X = $15*X

$25 = $15*X - $10*X = $5*X

X = 25/5 = 5

This means that if he buys 5 rosebushes, he will pay the same amount in both places.

If he buys less than 5 rosebushes, he will pay less in the local nursery (as it has a bigger slope, but no initial fee)

If he buys more than 5 rosebushes, he will pay less in the Garden club (because it has a smaller slope)

5 0

4 years ago

TIMOROW DUE HELP NOW

Svetlanka [38]

The required percentage error when estimating the height of the building is 3.84%.

<h3>How to calculate the percent error?</h3>

Suppose the actual value and the estimated values after the measurement are obtained. Then we have:

Error = Actual value - Estimated value

Given that,

An estimate of the height, H meters, of a tall building can be found using the formula :

H = 3f + 15

where the building is f floors high.

f = 85

The real height of the building is 260 m.

H = 3f + 15

Put f = 85 in the above formula

H = 3(85) + 15

H = 270 m

Error,

$E = \dfrac{270 - 260 }{260} \times 100\\\\E = 3.84 %$

So, the required percentage error is 3.84%.

Learn more about percentage error;

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3 0

2 years ago

What value for x will make the equation true?

Rama09 [41]

Answer:

C . 4

Step-by-step explanation:

step 1 : -3 multiply with inside of the ( 7x-5 )

= -21x + 15

step 2 : then it will be 21x + 15 = 87 + 3x

step 3 : switch between the odds into like this

21x - 3x = 87 - 15

step 4 : subtract it all

18x = 72

step 5 : bring 18 to the other side

x = 72/18

step 6 : to find the ans of x is just calculate them

x = 72 ÷ 18

= 4

Or you can do like these ⬇️

-3 ( 7x - 15 ) = 87 + 3x

21x + 15 = 87 + 3x

21x - 3x = 87 - 15

18x = 72

x = 72/18 or 72÷18

x = 4

4 0

3 years ago

Consider an experiment where two 6-sided dice are rolled. We can describe the ordered sample space as below where the first coor

agasfer [191]

Answer:

$E$ = { (4,1) , (3,2) , (2,3) , (1,4) }

$P(E)=\frac{1}{9}$

$P(F|E)=\frac{1}{4}$

Step-by-step explanation:

Let's start writing the sample space for this experiment :

$S=$ { (1,1) , (1,2) , (1,3) , (1,4) , (1,5) , (1,6) , (2,1) , (2,2) , (2,3) , (2,4) , (2,5) , (2,6) , (3,1) , (3,2) , (3,3) , (3,4) , (3,5) , (3,6) , (4,1) , (4,2) , (4,3) , (4,4) , (4,5) , (4,6) , (5,1) , (5,2) , (5,3) , (5,4) , (5,5) , (5,6) , (6,1) , (6,2) , (6,3) , (6,4) , (6,5) , (6,6) }

Let's also define the event $E$ ⇒

$E$ : '' The sum of the two dice is 5 ''

We can describe the event by listing all the favorables cases from $S$ ⇒

$E$ = { (4,1) , (3,2) , (2,3) , (1,4) }

In order to calculate $P(E)$ we are going to divide all the cases favorables to $E$ over the total cases from $S$ . We can do this because all 36 of these possible outcomes from $S$ are equally likely. ⇒