What is the diameter of (7/3,-2/3), (2,3/2)
1 answer:
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Answer:
B)3x^2 (4*x^2 + 2x + 6)
Step-by-step explanation:
Step 1: Find the Greatest common factor of the given expression.
12x^4 + 6x^3 + 18x^2
The above expression can be written as .
= 2*2*3*x^4 + 2*3*x^3 + 2*3*3*x^2
Here 3x^2 is prime factor
Step 2: Let's take out the 3 and write the remaining terms in the parenthesis.
= 3x^2 (2*2*x^2 + 2x + 2*3)
= 3x^2 (4x^2 + 2x + 6)
Therefore, the answer is B)3x^2 (4*x^2 + 2x + 6)
Thank you.
