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Lisa [10]
2 years ago
9

Determine the perimeter of a rectangle with a length of 2 feet and a width of 6 inches. (Multiple choice)

Mathematics
1 answer:
Ray Of Light [21]2 years ago
4 0

Answer:

D or 16

Step-by-step explanation:

For perimeter, the formula is 2(L + W) where L is length, and W is width.

So 2 ( 2 + 6 )

= (4 + 12)

= 16

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Pls help me with the inverse operation of this problem. Best answer gets brainliest
timurjin [86]

Answer:

x=7

Step-by-step explanation:

I believe we are solving for x. In that case, let us start by moving 1 to the other side.

\frac{4(x+3)}{5} = 8

Now, we want to get rid of that denominator of 5. Let us multiply both sides by 5:

4(x+3)=40

Now, we may divide both sides by 4 to get rid of the coefficiant:

x+3=10

When we subtract both sides by 3, we get

x=7

<em>I hope this helps! :)</em>

6 0
2 years ago
70 POINTS SHOW WORK
lord [1]
Area of triangle = 1/2 x base x height

so old triangle we have  1/2 x b x h = 48

new triangle has base 3 times as long and height is half as long
 so we would get:

1/2 x (3B) x (1/2H) = area

rewrite as 1/2 x 3/2 x b x H = area

divide by original are os 1/2 x b x h and you end up with 3/2

so new area = 3/2 x old area

new area = 3/2 * 48 = 72 square inches
8 0
3 years ago
Read 2 more answers
There are two bowls. One of them has 60 gems and the other has 40 gems. Some of them are red. All the gems from the two bowls ar
uranmaximum [27]

Answer:

60/40

the awnser for the question is 3/2

5 0
2 years ago
Piper has a balance of $1,500 on
saul85 [17]

Answer: $408.96

Step-by-step explanation:

4 0
2 years ago
Please help! A-level maths.
astra-53 [7]

x+y=k\implies y=k-x

Substitute this into the parabolic equation,

k-x=6-(x-3)^2\implies x^2-7x+(k+3)=0

We're told the line x+y=k intersects C twice, which means the quadratic above has two distinct real solutions. Its discriminant must then be positive, so we know

(-7)^2-4(k+3)=49-4(k+3)>0\implies k

We can tell from the quadratic equation that C has its vertex at the point (3, 6). Also, note that

-1\le\sin t\le1\implies3\le3+2\sin t\le5\implies3\le x\le5

and

-1\le\cos2t\le1\implies2\le4+2\cos2t\le6\implies2\le y\le6

so the furthest to the right that C extends is the point (5, 2). The line x+y=k passes through this point for 2+5=k\implies k=7. For any value of k, the line x+y=k passes through C either only once, or not at all.

So 7\le k; in set notation,

\{k\mid 7\le k

4 0
3 years ago
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