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3 years ago

A basketball player made 57 out of 100 attempted free throws. What percent of free throws was made?

Mathematics

2 answers:

Effectus [21]3 years ago

6 0

57% of free throws were made

Rom4ik [11]3 years ago

3 0

57 out of 100 = 57/100 = 57%

Hope this helps!

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For the last three months Olivia saved $75, $95, and $84. What is the minimum amount she should save next month in order to save

goblinko [34]

The answer is 106 dollars

8 0

3 years ago

PLEASE HELP!!! WORTH 20 POINTS!

Mkey [24]

Answer:

a. 1 1/2 (or 3/2)

b. 2/3

c. 1

d. 1

Step-by-step explanation:

Part A: (1,1) (7,5)

To determine the slope, you will use the equation m=(y2-y1)/(x2-x1). Keep in mind that it doesn't matter what point you use for (x1, y1) or (x2, y2).

Let's plug in the numbers for part a:

m=(7-1)/(5-1)

Let's then solve the problems inside the parentheses:

m=6/4

And finally, we simplify:

m=3/2 (or 1 1/2 depending on what your teacher wants for an answer)

For these others, I will just go through the steps and not explain them, if you need help or don't understand something I'm doing, either look back at what I did for part a or comment on this answer.

Part B: (1,1) (5,7)

m=(5-1)/(7-1)

m=(4/6)

m=2/3

Part C: (2,5) (-1,2)

m=(-1-2)/(2-5)

m=(-3/-3)

m=1

Part D: (2,5) (-7,-4)

m=(-7-2)/(-4-5)

m=(-9/-9)

m=1

8 0

2 years ago

Please help ASAP! I will mark Brainliest! Please READ the question THEN answer CORRECTLY! No guessing!

Alja [10]

Answer:

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Please help solve for x..

aalyn [17]

Answer:

x = 1 or x = -1

Step-by-step explanation:

Given equation:

$x^{100}-4^x \cdot x^{98}-x^2+4^x=0$

Factor out -1:

$\implies -1(-x^{100}+4^x \cdot x^{98}+x^2-4^x)=0$

Divide both sides by -1:

$\implies -x^{100}+4^x \cdot x^{98}+x^2-4^x=0$

Rearrange the terms:

$\implies 4^x \cdot x^{98}-4^x-x^{100}+x^2=0$

$\textsf{Apply exponent rule} \quad a^{b+c}=a^b \cdot a^c \quad \textsf{to }x^{100}:$

$\implies 4^x \cdot x^{98}-4^x-x^{98}x^2+x^2=0$

Factor the first two terms and the last two terms separately:

$\implies 4^x(x^{98}-1)-x^2(x^{98}-1)=0$

Factor out the common term $(x^{98}-1)$ :

$\implies (4^x-x^2)(x^{98}-1)=0$

<u>Zero Product Property</u>: If a ⋅ b = 0 then either a = 0 or b = 0 (or both).

Using the <u>Zero Product Property</u>, set each factor equal to zero and solve for x (if possible):

$\begin{aligned}x^{98}-1 & = 0 & \quad \textsf{or} \quad \quad4^x-x^2 & = 0 \\x^{98} & =1 & 4^x & = x^2 \\x & = 1, -1 & \textsf{no}& \textsf{ solutions for } x \in \mathbb{R}\end{aligned}$