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Aleksandr-060686 [28]

3 years ago

14

Help. zoom in thank you if you help plz

2 answers:

Troyanec [42]3 years ago

8 0

Multiply by b x h

b=base

h=height

and you will get your answer

snow_lady [41]3 years ago

6 0

If you use the formula
A = B ✖️ H
A= Area
B=Base
H=Height

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Cotpheta•sin2pheta=<br><br>1+cos2pheta<br>1+cospheta<br>1+sin2pheta

3241004551 [841]

Answer:

Step-by-step explanation:

Did you mean.

$= \cot( \theta) . \sin(2 \theta)$

$= \frac{ \cos( \theta) }{ \sin( \theta) } .(2 \sin( \theta) \cos( \theta) )$

$= \frac{2 \sin( \theta) \cos {}^{2} ( \theta) }{ \sin( \theta) }$

$= 2 \cos {}^{2} ( \theta)$

$= 2.(1 - \sin {}^{2} ( \theta) )$

$= 2 - 2 \sin {}^{2} ( \theta)$

No option Solution.

8 0

2 years ago

Which property of exponents must be used first to solve this expression? (xy^2)^1/3

Ratling [72]

(ab)n=anbn......................................

3 0

3 years ago

Read 2 more answers

A man is 5 feet 9 inches tall. To find the height of a tree, the shadow of the man and the shadow of

12345 [234]

Answer:

ur answer is B. 17.25

Step-by-step explanation:

Hope this helps :D!

3 0

2 years ago

Read 2 more answers

Order them from smallest to largest.

atroni [7]

X + x + x
7x - x
3x + 2x + 3x
2 (5x)
12x - 8r + 3r - 2x

6 0

3 years ago

I would like some help thank you :)

pantera1 [17]

Answer:

$\angle AE = 32^{\circ}$

$\angle EAD = 212^{\circ}$

$\angle BE = 133^{\circ}$

$\angle BCE = 227^{\circ}$

$\angle AED = 180^{\circ}$

$\angle BD = 79^{\circ}$

Step-by-step explanation:

The central angle of a circle is equal to 360º, whose formula in this case is:

$\angle AB + \angle BC + \angle CD + \angle DE + \angle EA = 360^{\circ}$

In addition, the following conditions are known from figure:

$\angle BC = 47^{\circ}$ , $\angle DE = 148^{\circ}$

$\angle DE + \angle EA = 180^{\circ}$

$\angle CD + \angle DE = 180^{\circ}$

$\angle AB + \angle BC + \angle CD = 180^{\circ}$

Now, the system of equations is now solved:

$\angle EA = 180^{\circ}-\angle DE$

$\angle EA = 180^{\circ}-148^{\circ}$

$\angle EA = 32^{\circ}$

$\angle CD = 180^{\circ}-\angle DE$

$\angle CD = 180^{\circ}-148^{\circ}$

$\angle CD = 32^{\circ}$

$\angle AB = 180^{\circ} - \angle BC - \angle CD$

$\angle AB = 180^{\circ}-47^{\circ}-32^{\circ}$

$\angle AB = 101^{\circ}$

The answers are described herein:

$\angle AE = 32^{\circ}$

$\angle EAD = 212^{\circ}$

$\angle BE = 133^{\circ}$

$\angle BCE = 227^{\circ}$

$\angle AED = 180^{\circ}$

$\angle BD = 79^{\circ}$

7 0

3 years ago