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STALIN [3.7K]
3 years ago
13

)A scanner scanned 63 photos in 9 minutes. If it scans photos at a constant rate, it can scan _____ photos in 21 minutes.

Mathematics
1 answer:
Cloud [144]3 years ago
3 0

Answer:

147 photos

Step-by-step explanation:

63 photos -> 9 minutes

To find the number of photos scanned per minute, divide both sides by 9.

63\div 9=7 photos -> 1 minute

To find 21 minutes, we can do 21\times 7=147

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<h3>Answers:     x = -17  and   x = 64</h3>

====================================================

Explanation

Consider three scenarios:

  • A) The value of x is the smallest of the set (aka the min)
  • B) The value of x is the largest of the set (aka the max)
  • C) The value of x is neither the min, nor the max. So 8 < x < 39.

These scenarios cover all the possible cases of what x could be. It's either the min, the max, or somewhere in between the min and max.

--------------------

We'll start with scenario A.

If x is the min, then that must mean 39 is the max as it's the largest of the set {18, 36, 16, 39, 27, 8, 34}

The range is 56, so,

range = max - min

56 = 39 - x

56+x= 39

x = 39-56

x = -17  which is one possible answer

--------------------

If instead we go with scenario B, then x is the max and 8 is the min

range = max - min

56 = x - 8

56+8 = x

64 = x

x = 64 is the other possible answer

--------------------

Lastly, let's consider scenario C. If x is not the min or the max, then it's somewhere between the min 8 and max 39. in short, 8 < x < 39.

Note that range = max - min = 39-8 = 31 which is not the range of 56 that we want. So there's no way scenario C can be possible here.

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