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il63 [147K]
3 years ago
11

At the start of the month, the value of an investment was $48.45. By the end of the month, the value of the investment changed b

y a loss of $13.80. What was the value, in dollars, of the investment at the end of the month?
Mathematics
1 answer:
Klio2033 [76]3 years ago
4 0
$34.65 because of 48.45-13.80
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In circle O, AD and BE are diameters. What is MAE?
liraira [26]

Answer:

132°

Step-by-step explanation:

∠AOB = ∠EOD = 3x ( vertical angles )

∠AOB + ∠BOC = 90, that is

3x + 0.5x + 34 = 90

3.5x + 34 = 90 ( subtract 34 from both sides )

3.5x = 56 ( divide both sides by 3.5 )

x = 16

∠AOE + ∠EOD = 180 ( straight angle )

∠AOE + 3x = 180

∠AOE + (3 × 16) = 180

∠AOE + 48 = 180 ( subtract 48 from both sides )

∠AOE = 132°



5 0
3 years ago
Read 2 more answers
What is the sum of the geometric series
Sergio039 [100]
Answer: 2343 / 256

Explanation

I will do this for you in two forms: 1) adding each term, and 2) using the general formula for the sum of geometric series.

1) Adding the terms:

 4
∑ 3 (3/4)^i = 3 (3/4)^0 + 3 (3/4)^1 + 3 (3/4)^2 + 3 (3/4)^3 + 3 (3/4)^4
i=0

= 3 + 9/4 + 27/16 + 81/64 + 243/256 = [256*3 + 27*16 + 64*9 + 4*81 + 243] / 256 =

= 2343 / 256

2) Using the formula:

n-1
∑ A (r^i) = A [1 - r^(n) ] / [ 1 - r]
i=0

Here n - 1 = 4 => n = 5

r = 3/4

A = 3

Therefore the sum is 3 [ 1 - (3/4)^5 ] / [ 1 - (3/4) ] =

= 3 [ 1 - (3^5) / (4^5) ] / [ 1/4 ] = 3 { [ (4^5) - (3^5) ] / (4^5) } / {1/4} =

= (3 * 781) / (4^5) / (1/4) =  3 * 781 / (4^4) = 2343 / 256

So, no doubt, the answer is 2343 / 256
5 0
4 years ago
A light bulb consumes 3600 watt-hours per day. How many watt-hours does it consume in 5 days and 6 hours?
Cerrena [4.2K]

Answer:

18900 watt-hours

Step-by-step explanation:

3600 x 24 (hours in a day) = 150

150 x 6 (hours) = 900

3600 (watt hours per day) x 5 (days) = 18000

18000 x 900 = 18900

total= 18900

8 0
3 years ago
Suppose a certain type of fertilizer has an expected yield per acre of mu 1 with variance sigma 2, whereas the expected yield fo
mart [117]

Answer:

See the proof below.

Step-by-step explanation:

For this case we just need to apply properties of expected value. We know that the estimator is given by:

S^2_p= \frac{(n_1 -1) S^2_1 +(n_2 -1) S^2_2}{n_1 +n_2 -2}

And we want to proof that E(S^2_p)= \sigma^2

So we can begin with this:

E(S^2_p)= E(\frac{(n_1 -1) S^2_1 +(n_2 -1) S^2_2}{n_1 +n_2 -2})

And we can distribute the expected value into the temrs like this:

E(S^2_p)= \frac{(n_1 -1) E(S^2_1) +(n_2 -1) E(S^2_2)}{n_1 +n_2 -2}

And we know that the expected value for the estimator of the variance s is \sigma, or in other way E(s) = \sigma so if we apply this property here we have:

E(S^2_p)= \frac{(n_1 -1 )\sigma^2_1 +(n_2 -1) \sigma^2_2}{n_1 +n_2 -2}

And we know that \sigma^2_1 = \sigma^2_2 = \sigma^2 so using this we can take common factor like this:

E(S^2_p)= \frac{(n_1 -1) +(n_2 -1)}{n_1 +n_2 -2} \sigma^2 =\sigma^2

And then we see that the pooled variance is an unbiased estimator for the population variance when we have two population with the same variance.

8 0
3 years ago
Find the value of x that makes ABCD a parallelogram.
ELEN [110]

Answer:

Step-by-step explanation:

130+5x=180

130-130+5x=180-130

5x=50

x=10

8 0
4 years ago
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