Yes it’s 15, Thats cool man
The problem deals with fractions comparison, lets do it:
21/30 > 2/3
we begin solving:
21 > (2/3)*30
21 > 2*10
<span>21 > 20
</span>therefore the proposed inequality is true, <span>21/30 > 2/3
You can solve as well getting same denominator for both fractions and comparing directly, in this case we need to get 2/3 to be divided by 30:
2/3 = (10/10)(2/3) = 20/30
So we have:
</span><span>21/30 > 2/3
</span>which is equal to:
<span>21/30 > 20/30
</span>and we compare directly because both fractions are divided by the same number, and we can see that the inequality is true.
Assuming the bases are laid out in a square, then we can use the Pythagorean Theorem to find the distance from home plate to second base.
This distance is exactly the length of the hypotenuse of the right triangle that forms when you split the square along the diagonal. Let this distance be x
Each of the legs are 90 ft, so a = 90 and b = 90. The hypotenuse is c = x for now.
a^2 + b^2 = c^2
90^2 + 90^2 = x^2
8100 + 8100 = x^2
16200 = x^2
x^2 = 16200
sqrt(x^2) = sqrt(16200) ... apply the square root to both sides
x = 127.2792206
x = 127.3 .... round to the nearest tenth (one decimal place)
The final answer is 127.3 feet
Answer:
23°
Step-by-step explanation:
For this scenario say point G is the center point,
If we look to the left, we see angle FGE has a value of 23
and in this case angle CGD is a congruent angle to FGE therefore the two angles must be the same
so therefore angle CGD should be 23 degrees
