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Sergio [31]
1 year ago
5

Complete the square 2m2−3m=−50

Mathematics
1 answer:
rusak2 [61]1 year ago
4 0

Answer:

Completing the square answer

\left(m  - \frac{3}{4}\right)^2 =  - \frac{391}{16}

Solution set

m = \frac{3}{4} + \frac{\sqrt[]{391}i}{4} = 0.75 + 4.94343 \, i

m = \frac{3}{4} - \frac{\sqrt[]{391}i}{4} = 0.75 - 4.94343 \, i

Step-by-step explanation:

Assuming the question is correctly interpreted as 2m2 = 2m², here is how to proceed

We have 2m^2 - 3m =-50

Divide by 2 on both sides

m^2 - \frac{3}{2}m =  - 25

Take half of the  coefficient of x and square it

\left[  - \frac{3}{2} \cdot \frac{1}{2} \right]^2 = \frac{9}{16}

Add the result to both sides

m^2 - \frac{3}{2}m + \frac{9}{16} =  - 25 + \frac{9}{16}

m^2 - \frac{3}{2}m + \frac{9}{16} can be re-written as a perfect square

\left(m  - \frac{3}{4}\right)^2

The RHS becomes

- 25 + \frac{9}{16} = \frac{(-25)(16) + 9}{9} = \frac{-391}{16}

Therefore,

\left(m  - \frac{3}{4}\right)^2 =  - \frac{391}{16}

Take the square root of both side

m  - \frac{3}{4} = \pm \sqrt[]{ - \frac{391}{16}}

Simplify

m  - \frac{3}{4} = \pm \frac{\sqrt[]{391}i}{4}

Adding \frac{3}{4} both sides

m = \frac{3}{4} + \frac{\sqrt[]{391}i}{4}

This gives the two solutions

m= \frac{3}{4} + \frac{\sqrt[]{391}i}{4}  and

m = \frac{3}{4} - \frac{\sqrt[]{391}i}{4}

which becomes

m = 0.75 + 4.94343 \, i and

m = 0.75 - 4.94343 \, i

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