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NemiM [27]
3 years ago
8

Simplify the expression. 9n - 3n + 5.

Mathematics
2 answers:
Greeley [361]3 years ago
5 0
6n+5, because you just subtract 9n with 3n
irina1246 [14]3 years ago
3 0
Let's simplify step-by-step.
9n−3n+5
=9n+−3n+5
Combine Like Terms:
=9n+−3n+5
=(9n+−3n)+(5)
=6n+5
Answer:
=6n+5
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help with number 2 please i have no idea how to do this. it would be very helpful if you can show the steps
zloy xaker [14]
So in this case, we have to replace the known value.
y=3
y=-2x+3

3=-2x+3

Then we leave our unknown value alone.
\frac{3-3}{2}= x

In this case, our x value would be 0.

We check it...
3=-2(0)+3
3=0+3
3=3

So y=3 x=0

For the second one we have...
y=3x+2
y=-3x-4

For this we substitute the y in any of the equation...
3x+2=-3x-4

We move the unknown values to one side and the ones without unlown values to the other side...
3x+3x=-4-2

Then we solve
6x=-6

Then we leave the unknown value alone.
x=\frac{-6}{6}

Then solve for x.
x= -1

Then for our y value we return to one of the original equations and substitute the x value.
y=3x+2
y=3(-1)+2
y=-3+2
y=-1

y=-3x-4
y=-3(-1)-4
y=3-4
y=-1

So in this case we got that x= -1 and y= -1
4 0
3 years ago
(3^n*3^2)^4=3^28<br> Enter the value of n for the equation<br> N= ?
maksim [4K]
Hello! And thank you for your question!

Use Pemdas to get

3^(n+2)*4=3^28

Rewrite the equation:

3^4(n+2) = 3^28

Cancel the base of 3:

4(n + 2) = 28

Then divide 4 on both sides:

2 + n = 28/4

Simplify 28/4:

2 + n = 7

Subtract 2 on both sides:

n = 7 - 2

Finally simplify 7 - 2:

n = 5

Final Answer:

n = 5
8 0
3 years ago
Find range of the following function
Marina CMI [18]

Answer:

4x to the power of 2

Step-by-step explanation:

3 0
3 years ago
What are the coordinates of the midpoint of the line segment with endpoints R(4,−7) and S(−3,5)?
tekilochka [14]
The answer is (.5,-1)
3 0
3 years ago
How can i rewrite that with exponents instead of repeated multiplication
Montano1993 [528]

Answer:

10^12

Step-by-step explanation:

Add the exponents when you multiply numbers with exponents

8 0
3 years ago
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