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Anna35 [415]
4 years ago
12

How do i add 1 1/6+ 3/5

Mathematics
2 answers:
Ierofanga [76]4 years ago
3 0
You would change the denominator and get the lowest common denominator. Thos would be 30. You would do 11/6 x 5/5 = 55/30. Then do 3/5 x 6/6 = 18/30. Then add 55/30 + 18/30 = 73/30 and simplify.
Sidana [21]4 years ago
3 0
Find the least common denominator
6 and 5 least common factor is 30
So multiply each number to get 30

11/6 x5 = 55/30

3/5x6= 18/30

55/30+18/30 = 68/30

Simplified

34/15
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What is the value of 'c' so that -9 and 9 are both solutions of x^2+c=103?
Gnoma [55]

Answer:

c = 22

Step-by-step explanation:

x^2 + c = 103 so if x is either + or - 9, x^2 = 81 so...

81 + c = 103

c = 22

4 0
4 years ago
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The low temperature during 4 days in September was 21°C, 21°C, 19°C and 19°C. What was the mean temperature?
Snowcat [4.5K]

Answer:

Step-by-step explanation:

The Answer is 20.

1: First, add up all the temperatures that has been provided, 21 + 21 + 19 + 19. It should give you 80.

2: Divide 80 by how many temperatures has been shown. There were 4 temperatures shown, so 80/4 = 20. Hope this helps you!

5 0
3 years ago
1
Minchanka [31]

Answer:

a

Step-by-step explanation:

6 0
3 years ago
According to the 2011 National Survey of Fishing, Hunting, and Wildlife-Associated Recreation, there were over 71 million wildif
suter [353]

Answer:

The probability that between 79% and 81%of the 500 sampled wildlife watchers actively observed mammals in 2011 is P=0.412.

Step-by-step explanation:

We know the population proportion π=0.8, according to the 2011 National Survey of Fishing, Hunting, and Wildlife-Associated Recreation.

If we take a sample from this population, and assuming the proportion is correct, it is expected that the sample's proportion to be equal to the population's proportion.

The standard deviation of the sample is equal to:

\sigma_s=\sqrt{\frac{\pi(1-\pi)}{N}}=\sqrt{\frac{0.8*0.2}{500}}=0.018

With the mean and the standard deviaion of the sample, we can calculate the z-value for 0.79 and 0.81:

z=\frac{p-\pi}{\sigma}=\frac{0.79-0.80}{0.018} =\frac{-0.01}{0.018} = -0.55\\\\z=\frac{p-\pi}{\sigma}=\frac{0.81-0.80}{0.018} =\frac{0.01}{0.018} = 0.55

Then, the probability that between 79% and 81%of the 500 sampled wildlife watchers actively observed mammals in 2011 is:

P(0.79

3 0
3 years ago
\dfrac12\left(6e - 3f - \dfrac34\right) =
liraira [26]

Answer:

  3e - \dfrac32f - \dfrac38

Step-by-step explanation:

Use the distributive property to eliminate parentheses.

  \dfrac12\left(6e - 3f - \dfrac34\right)=\boxed{3e - \dfrac32f - \dfrac38}

6 0
3 years ago
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