All categories

3 years ago

Events C and D are____. P(A) = 1/3 P(B) = 1/3 P(A ∩ B) = 0 P(A | B) ≠ 0

Mathematics

1 answer:

snow_tiger [21]3 years ago

6 0

The answer is A hope you get it right (:

You might be interested in

Will someone help with this ! I was allowed a retry for it and I don’t know how to do it

pashok25 [27]

Answer:

$\frac{dN}{dt}=k(725-N)\\separating the variables and integrating\\\int \frac{dN}{725-N}=\int kdt+c\\-log (725-N)=kt+c\\log (725-N)=-kt-c\\(725-N)=e^{-kt-c} =e^{-kt} *e^{-c} =Ce^{-kt} \\when t=0,N=400\\725-400=Ce^{0} =C\\C=325\\when t=3,N=650\\725-650=325e^{-3k} \\\frac{75}{325}=(e^{-k})^3\\\\e^{-k} =(\frac{3}{13}) ^{\frac{1}{3} } \\when t=5\\725-N=325(\frac{3}{13}) ^{\frac{5}{3} } =325*\frac{3}{13}*(\frac{3}{13} )^{\frac{2}{3}}\\N=725-75*(\frac{3}{13} )^{\frac{2}{3} }=725-28=697$

Step-by-step explanation:

6 0

3 years ago

The perimeter of a rectangular window is 43 feet. The width of the window is 5 ft more than the length. Find the width of the wi

Greeley [361]

Answer:

13.25 ft

Step-by-step explanation:

Let w represent the width of the window. Then w-5 represents the length, and the perimeter is ...

P = 2(L+W)

43 = 2((w-5) +w) = 4w -10

53/4 = w = 13.25 . . . feet

The width of the window is 13.25 ft.

8 0

2 years ago

Read 2 more answers

Question 2b only! Evaluate using the definition of the definite integral(that means using the limit of a Riemann sum

lara [203]

Answer:

Hello,

Step-by-step explanation:

We divide the interval [a b] in n equal parts.

$\Delta x=\dfrac{b-a}{n} \\\\x_i=a+\Delta x *i \ for\ i=1\ to\ n\\\\y_i=x_i^2=(a+\Delta x *i)^2=a^2+(\Delta x *i)^2+2*a*\Delta x *i\\\\\\Area\ of\ i^{th} \ rectangle=R(x_i)=\Delta x * y_i\\$

$\displaystyle \sum_{i=1}^{n} R(x_i)=\dfrac{b-a}{n}*\sum_{i=1}^{n}\ (a^2 +(\dfrac{b-a}{n})^2*i^2+2*a*\dfrac{b-a}{n}*i)\\$

$=(b-a)^2*a^2+(\dfrac{b-a}{n})^3*\dfrac{n(n+1)(2n+1)}{6} +2*a*(\dfrac{b-a}{n})^2*\dfrac{n (n+1)} {2} \\\\\displaystyle \int\limits^a_b {x^2} \, dx = \lim_{n \to \infty} \sum_{i=1}^{n} R(x_i)\\\\=(b-a)*a^2+\dfrac{(b-a)^3 }{3} +a(b-a)^2\\\\=a^2b-a^3+\dfrac{1}{3} (b^3-3ab^2+3a^2b-a^3)+a^3+ab^2-2a^2b\\\\=\dfrac{b^3}{3}-ab^2+ab^2+a^2b+a^2b-2a^2b-\dfrac{a^3}{3} \\\\\\\boxed{\int\limits^a_b {x^2} \, dx =\dfrac{b^3}{3} -\dfrac{a^3}{3}}\\$

4 0

2 years ago

Jessica and Emily went shopping at a local boutique. Jessica purchased 4 bracelets and a new.pair of earrings for $9.50. Emily p

Radda [10]

What’s the complete question

5 0

3 years ago

Help me with problem

DENIUS [597]

Answer:

x = 16.67

Step-by-step explanation:

4x - 6 + 8x - 6 = 180

12x - 14 = 180

+ 14 + 14

12x = 194

/ 12 / 12

x = 16.67

4 0

2 years ago