Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.
We are to find the probability of selecting 1 red apple and 2 yellow apples.
Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.
Then, we have

Therefore, the probability of event A is given by

Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
The diagonals bisect each other
Answer:
D. x=1
Step-by-step explanation:
Image can be rewritten as 3x + 6 = 9.
Solve for x.
3x +6 = 9
Isolate x by subtracting 6 from both sides.
3x = 3
Get rid of the 3 by dividing by 3 on both sides.
x = 1
Hope this helped.
Answer:
-2
Step-by-step explanation:
= -2
I hope this helps!