Question

The perimeter of a rectangle is 46 in and the diagonal is 17 in. Find the area of the rectangle.

Answer 1

P=2*(L+l)=46
L+l=46:2
L+l=23
(L+l)^2=529
(L^2+l^2)+2l*L=529

D= V L^2+l^2= 17
L^2+l^2=289

so 289+2l*L=529
     2l*L=529-289=240
l*L=240:2
A=120