3 years ago

The perimeter of a rectangle is 46 in and the diagonal is 17 in. Find the area of the rectangle.

1 answer:

5 0

P=2*(L+l)=46
L+l=46:2
L+l=23
(L+l)^2=529
(L^2+l^2)+2l*L=529

D= V L^2+l^2= 17
L^2+l^2=289

so 289+2l*L=529
2l*L=529-289=240
l*L=240:2
A=120

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