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erastova [34]
4 years ago
9

Which of the following correctly uses absolute value to show the distance between -60 and 11? (5 points)

Mathematics
1 answer:
nexus9112 [7]4 years ago
8 0
The correct answer for this question is this one: "<span>|-60 - 11| = |-71| = 71 units"

The statement says that "the </span><span>absolute value that show the distance between -60 and 11"

Absolute value is the distance of that specific number from zero in a straight number line. The selected answer  is the correct one.</span>
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Which number line correctly shows –0.8 + 0.6? A number line going from negative 1.6 to positive 1.6. An arrow goes from negative
Phoenix [80]

Answer:

Hi there, are you sure you didn't forget any parenthesis or signs? I can't find the right answer in the options, the one that would end up at -0.2 in the end I can edit my answer if you tell me some additional option or info about the expression I need to show on the number line

Step-by-step explanation:

which number line shows correctly -0.8 + 0.6?

well lets write it in words minus eight tenths plus six tenths\

so minus:

you go 0.8 units to the left from 0,

then plus:

you go 0.6 units right from -0.8, getting to -0.2

since there is no exact answer like that we can rearrange the addends 0.6-0.8, now:

we go from 0 6 tenths units to the right and get to 0.6, then we go from 0.6 eight tenths unit to the left to get to -0.2

4 0
3 years ago
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4 years ago
The Polar Express
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Answer:

for 12-8: 33.33

or

for 8-4: 50

or

for 12-4: 66.67

Step-by-step explanation:

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3 years ago
Jared a beekeeper placed 120 hives in a apple orchard
Shtirlitz [24]

Answer: 20

Step-by-step explanation:

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3 years ago
If you draw four cards at random from a standard deck of 52 cards, what is the probability that all 4 cards have distinct charac
mezya [45]

There are \binom{52}4 ways of drawing a 4-card hand, where

\dbinom nk = \dfrac{n!}{k!(n-k)!}

is the so-called binomial coefficient.

There are 13 different card values, of which we want the hand to represent 4 values, so there are \binom{13}4 ways of meeting this requirement.

For each card value, there are 4 choices of suit, of which we only pick 1, so there are \binom41 ways of picking a card of any given value. We draw 4 cards from the deck, so there are \binom41^4 possible hands in which each card has a different value.

Then there are \binom{13}4 \binom41^4 total hands in which all 4 cards have distinct values, and the probability of drawing such a hand is

\dfrac{\dbinom{13}4 \dbinom41^4}{\dbinom{52}4} = \boxed{\dfrac{2816}{4165}} \approx 0.6761

4 0
2 years ago
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