We know that
Right triangles PBM and MTF are similar 
because
angle PMB=angle TMF
and
angle BPM=angle FTM
and 
angle B =angle F=90 degrees
so
corresponding sides are
BM and MF
PB and TF
PM and MT
(PB/TF)=BM/MF
solve for PB
PB=(TF*BM)/MF
where
TF=6ft
BM=20 ft
MF=3 ft
so
PB=(6*20)/3------> 40 ft
the answer is
<span>the height of the peak is 40 ft</span>
        
             
        
        
        
Answer:
C: (1,3)
Step-by-step explanation:
If we count 1 to the right on the x-axis and count 3 up on the y-axis, we will end up at the point of intersection which is (1,3).
 
        
             
        
        
        
Answer:

Step-by-step explanation:
<em>Given:</em>
Mn is diameter of circle having centre O
and BD = OD,
<em><u>To prove that:</u></em>
<u> </u>
</u>
<em>Solution:</em>
Join the points O and B and draw OB,
On joining the line, 
in ∆OCD and ∆OBD,
OC =OB → (Radius of same circle)
BD =CD → (from given)
OD =OD → (Common side in both the triangles)
Hence ∆OCD and ∆OBD are congruent from SSS property.
so we can say that,

Consider above prove as statement A
Corresponding angles of congruent traingle.
in ∆ OAB,
OA = OB (radius of same circle)
hence ∆OAB is an isosceles traingle.
We know that opposite angle of isosceles traingle are always equal. hence,

Consider above prove as statement B
From Statement A & B we can say that

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Answer:
vertex = (3,24)  Axis of symmetry = 3
Step-by-step explanation:
Use the vertex formula to find x: x=-b/2(a)
x= 12/2(2) = 3 (this is your axis of symmetry)
Substitute 3 for x in the equation to get y: y = 42
Once you have both x and y you have your vertex. 
 
        
             
        
        
        

Let's solve for x ~ 




Therefore, the possible values of x are 0 and 3