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blondinia [14]
3 years ago
11

Find the value of X: 3x (-35) = 2x

Mathematics
1 answer:
kobusy [5.1K]3 years ago
5 0
X=0
Pls mark brainliest
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Given f (x) = 2x+3 and g(x) = 4x + 3, find each of the following.<br> b. f(4) =<br> a. g(-2)=
olga nikolaevna [1]

Answer:

Step-by-step explanation:

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8 0
2 years ago
Can someone solve what y=?
ladessa [460]

Answer:

y = 1

Step-by-step explanation:

This is because the line intersects the y-axis at 1.

4 0
2 years ago
Read 2 more answers
-11 - 5a = 6(5a + 4) but I really need it in mathematical form. ​
ella [17]

Answer:

Step-by-step explanation:

In this equation what is strange is probably using the letter a as the unknown, but this is a matter of choice we could have calle y or z for that matter. Then we will treat it ans any other equation and solve it.

-11 -5a = 6(5a+4)

-11 -5a= 30a + 24

-11 - 24 = 30a + 5a   (placing the unknown a in the rght side and the numbers in the left to solve the equation)

- 35 = 35a

-35/35 = a

- 1= a

6 0
3 years ago
Help me please I need help in this math
Dmitrij [34]

Answer:

Step-by-step explanation:

AB

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2km 4mins

rate: 1km\minute

BC

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rate:0.83km\minute

CD

niether

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no rate

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8 0
3 years ago
How <br> do you write (-∞, 8) or (10, ∞) as an inequality?
ahrayia [7]

Your answer would be, To write, (−∞,8), or (10,∞), ==> x < 8 or, x > 10

(-∞, 8) or (10, ∞)

Solution: ==> - 10 . ∞ + 8 . ∞ or, x < 8 or, x > 10

Steps:

(-∞, 8) or (10, ∞) ==> - 10 . ∞ + 8 . ∞

(-∞, 8) . (10, ∞)

Computing dot product of two Vectors:

( X1, Xn) . ( Y1, Yn) = Σ^n^i = 1X^iY^i

= ( - ∞) . 10 + 8 . ∞

Simplify:

( - ∞) 10 + 8 . ∞

- 10 . ∞ + 8 . ∞

( - ∞) . 10 + 8 . ∞

Remove Parenthesis:

( - a) ==> - a

- ∞ . 10 + 8 . ∞

==> - 10 . ∞ + 8 . ∞

==> (- 10 . ∞ + 8 . ∞) ==> - 10 . ∞ + 8 . ∞

( ==> - 10 . ∞ + 8 . ∞)

Remove Parenthesis:

( a) = a

==> - 10 . ∞ + 8 . ∞

Therefore, (-∞, 8) or (10, ∞) as an inequality, Answers are, ==>

- 10 . ∞ + 8 . ∞ or, x < 8 or, x > 10

Check:

(-∞, 8) or (10, ∞)

==> x < 8 or, x > 10

Solution:

x < 8 or, x > 10

Interval Notation:

[ x < 8 or, x > 10 ==> (-∞, 8) ∪ (10, ∞) ]

Steps:

x < 8 or, x > 10

x < 8 : x < 8

x < 8

x < 8

x < 8

x > 10 : x > 10

x > 10

x > 10

x > 10

Combine The Ranges:

x < 8, or x > 10

Hope that helps!!!!! : )

4 0
3 years ago
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