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Blizzard [7]
3 years ago
11

What is this answer

Mathematics
1 answer:
Radda [10]3 years ago
4 0

use the distance formula

\sqrt{(x2-w1)^{2} +(y2-y1) ^{2}  }

You ll need to do it t times:

                       x1     y1      x2    y2

(-1, 5) (4, 2) =   (-1,     5)     (4,     2)

(4, 2) (0,0)

(0,0) (5,5)

(5,5) (-1, 5)

then add all your results

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when atc has not imposed any climb or descent restrictions and aircraft are within 1,000 feet of assigned altitude, pilots shoul
ziro4ka [17]

In the absence of ATC restriction on climb or descent, and aircraft are within 1,000 feet of assigned altitude. pilots should attempt to both climb and descend at a rate of between 500 fpm and 15000 fpm. (Option A)

An Air Traffic Controller (ATC) clearance refers to an authorization by ATC for the purpose of preventing known aircraft collision. The rate of climb or descend expected by ATV is when an aircraft is within 1000 feet of assigned altitude, descend, or climb at an optimum rate consistent with the operating characteristics of the aircraft to 1,000 feet above or below the assigned altitude, and then attempt to descend or climb at a rate of between 500 and 1,500 fpm until the assigned altitude is reached.

Learn more about Air Traffic Controller (ATC):

brainly.com/question/5018782

#SPJ4

7 0
1 year ago
Mr. Jackson invested a sum of money at 6% per year, and 3 times as much at 4%
bogdanovich [222]

Mr. Jackson invested $800 at 6% per year and $ 2400  at 4 % per year

<h3><u>Solution:</u></h3>

Mr. Jackson invested a sum of money at 6% per year, and 3 times as much at 4% per year.

Let the sum invested be ‘a’ and ‘3a’ at 6% per year and 4 % per year respectively

Also, his annual return totaled $144

We can form following equation on the basis of question:-

\begin{array}{l}{\text { Then, } \frac{a \times 6 \times 1}{100}+\frac{3 a \times 4 \times 1}{100}=\$ 144} \\\\ {\frac{6 a}{100}+\frac{12 a}{100}=144} \\\\ {\frac{6 a+12 a}{100}=144} \\\\ {\frac{18 a}{100}=144} \\\\ {18 a=14400} \\\\ {a=14400 \div 18}\end{array}

a = $800

The amount of money invested at 6% = a = 800

The amount of money invested at 4 % = 3a = 3(800) = 2400

So, the amount of money invested at 6% is $800 and the amount of money invested at 4% is $ 2400

4 0
2 years ago
(x3+3x2-12x-18)÷(x-3)
kvv77 [185]

Answer:

-3(3+4x)

Step-by-step explanation:

6 0
3 years ago
A robot packs boxes in a factory. It runs at a constant speed, and packs 5 boxes in 9 minutes. If the robot operated for 135 min
8090 [49]
I think the answer is 75.
6 0
2 years ago
Read 2 more answers
Which equation has exactly one solution?
KIM [24]
<h3>Answer: Choice B</h3>

===================================================

Explanation:

Let's look at choice A

The left hand side simplifies as follows

\frac{2+6x}{2}\\\\\frac{2}{2}+\frac{6x}{2}\\\\1+3x\\\\

This means the equation \frac{2+6x}{2}=3x+1\\\\ is the same as 1+3x=3x+1\\\\. Notice how the left and right sides are identical expressions. They both involve 3x and a 1. This means this equation has infinitely many solutions. We can rule out choice A.

------------------------------

I'll skip choice B and come back

Let's move onto choice C.

The given equation \frac{15x-5}{3}=5x+4\\\\ transforms into 5x-\frac{5}{3}=5x+4\\\\ through similar steps as choice A shows.

If we were to subtract 5x from both sides, all of the x terms go away on both sides. We'd be left with the equation -\frac{5}{3}=4\\\\ which is always false, which means that the original equation is always false.

Therefore, the equation of choice C has no solutions. We consider this equation inconsistent. We rule out choice C because of all this.

------------------------------

Choice D is pretty much the same as choice A even down to the conclusion of getting infinitely many solutions. The left hand side simplifies fully into the right hand side. The two sides are identical; hence, we have an identity. An identity is true for all allowed x values in the domain.

In other words, whatever x value you pick it will make the equation true. So we can rule this out because we want one solution only.

------------------------------

Only choice B is left. You'll notice that after simplifying the left hand side, the x term on the left side doesn't turn into 2x. So there's no way to get the options of "infinitely many solutions" or "no solutions". Those two cases only happen when we have the same x terms on both sides.

Put another way, the two slopes of each side are different which produces nonparallel lines that intersect at exactly one location. This intersection location is the solution. Specifically, the x coordinate of the (x,y) location is the solution.

5 0
2 years ago
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