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3 years ago

How do you do this question?

Mathematics

1 answer:

OLEGan [10]3 years ago

7 0

Step-by-step explanation:

∫ dt / (cos²(t) ⁹√(1 + tan(t)))

If u = 1 + tan(t), then du = sec²(t) dt.

∫ du / ⁹√u

∫ u^(-1/9) du

9/8 u^(8/9) + C

9/8 (1 + tan(t))^(8/9) + C

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One bus leaves a stop every 9 minute . A second bus leaves the stop every 15 minutes. If they both leave at 1:25 pm, at what tim

Verdich [7]

They will leave at1:70

8 0

2 years ago

A line segment has more then one midpoint true or false

Anika [276]

Answer:

false

Step-by-step explanation:

any line segment or distance has only one midpoint.

there is only one middle to everything.

how would that look like, if something had 2 middles ?

then they would not be a middle, and the middle between these 2 middles would then be the real middle ...

6 0

1 year ago

Read 2 more answers

How to factor 6n2 - 6n - 12

alexandr402 [8]

We see that in these 3 terms, 6 is a common factor. So, let's factor out a 6:

$6n^2-6n-12 = 6(n^2-n-2)$

We can set this equal to 0 and factor by using the quadratic formula which is:

$x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

So, let's do just that:

$6(n^2-n-2) = 0$

Note that the 6 goes away if you divide both sides by 6. In this case, a = 1, b = -1, and c = -2. Let's plug that into the quadratic equation:

$\frac{1 \pm \sqrt{(-1)^2-4(1)(-2)} }{2(1)} = \frac{-1 \pm \sqrt{1-(-8)} }{2}$

$\frac{-1 \pm \sqrt{9} }{2} = {1, -2}$

So, we can write this as:

$6n^2 - 6n - 12 = 6(n-1)(n+2)$

Notice that the 6 comes back because it was only temporarily mad. And that the roots have opposite signs in the parentheses because to find the roots, you need to set each parentheses equal to 0 and solve for n. With that in mind, your final answer is 6(n-1)(n+2). Hope I could help you!

7 0

2 years ago

Which fraction is equivalent to 0.3636...

NNADVOKAT [17]

A = 0.363636 ...
a = 0.(36)
100a = 36.(36)
100a - a = 36.(36) - 0.(36)
99a = 36
$a=\frac{36}{99}\\\\ a=\frac{4}{11}$