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marin [14]
3 years ago
15

Find the interquartile range (IQR) of the data in the box plot below.

Mathematics
2 answers:
den301095 [7]3 years ago
5 0

Answer:

IQR=0.2

Step-by-step explanation:

0.8-0.6=0.2

Sav [38]3 years ago
3 0

Answer:

0.2

Step-by-step explanation:

Median: 0.7

Lower quartile: 0.6

Upper quartile: 0.8

Interquartile range: 0.8 - 0.6 = 0.2

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A rental car company charges $40.18 per day to rent a car and $0.05 for every mile driven. Jacob wants to rent a car, knowing th
Harlamova29_29 [7]

Answer:

b) 270 ≥ 40.18d + 3.75

Step-by-step explanation:

Per day is a variable, so it's 40.18d

Per mile is also a variable so 0.05m

40.18d + 0.05m ≤ 270

40.18d + 0.05(75) ≤ 270

40.18d + 3.75 ≤ 270

5 0
3 years ago
Apples cost $3.45 per pound find the cost of 2.6 pounds of apples Solve this problem With multiplication​
lapo4ka [179]

Answer:

8.97

Step-by-step explanation:

3.45(2.6) = $8.97

Hope this helps you! :)

7 0
4 years ago
Someone help me with this??
marin [14]
The answer is ,c I took that same test and made a 95 on it
6 0
3 years ago
Need help now! (probibility)
algol13

Answer:

36%, I'm fairly certian

Step-by-step explanation:

A. 90%

B. 60%

C. 30%

D. 36%

D. makes the most sense to me

6 0
3 years ago
The difference of two perfect cubes is 386. If the cube root of the smaller of the two numbers is 7, then the cube root of the l
choli [55]

Answer:

9

Step-by-step explanation:

Let the two perfect cubes be x and y where x > y.

According to the given conditions:

{x}^{3}  -  {y}^{3}  = 386...(1) \\ y = 7...(2) \\ plug \: y = 7 \: in \: equation \: (1) \\  {x}^{3}  -  {7}^{3}  = 386 \\ {x}^{3}  -  343 = 386 \\ {x}^{3}     = 343  +  386 \\ {x}^{3}     = 343  +  386 \\ {x}^{3}   = 729 \\ x =  \sqrt[3]{729}  \\ x = 9

Thus the cube root of the larger number is 9.

8 0
4 years ago
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