A quadrilateral has vertices (2, 0), (0, –2), (–2, 4), and (–4, 2). Which special quadrilateral is formed by connecting the midp
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Steps of construction:
1. Draw a circle with centre B.
2. Draw a circle with centre C.
3. Both circles intersect each other at a point D
4. Join A and D.
5. So, AD bisects angle CAB.
<em>A </em><em>rough </em><em>figure </em><em>is </em><em>shown</em><em> </em><em>in </em><em>the </em><em>picture</em><em>.</em>
Answer:
Here's what I get
Step-by-step explanation:
I plotted the triangles in the diagram below.
Part A
The scale factor for dilation is ½, because every coordinate has been halved.
P (8, 0) ⟶ P' (4, 0)
Q (6, 2) ⟶ Q' (3, 1)
R (-2, -4) ⟶ R' (-1, -2)
Part B
When you reflect a point (x, y) about the y-axis, the y-coordinate remains the same, but the x-coordinate gets the opposite sign. Thus,
P' (4,0) ⟶ P" (-4,0)
Q' (3,-1) ⟶ Q" (-3,-1)
R' (-1,-2) ⟶ R" (1,-2)
∆P"Q"R" has coordinates P" (-4,0), Q" (-3,-1), R"(1,-2).
Part C
∆PQR and ∆ P"Q"R" are not congruent, because corresponding sides are not equal.
