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babunello [35]
3 years ago
5

Janet has a square-shaped sheet of wrapping paper. To cover the top of a box, she cuts off 11 centimeters of the sheet along the

width. The new area of the sheet is given by the expression below, where x represents the length, in centimeters, of the sheet of wrapping paper before being cut.
x^2-11x
Which statement best describes the term 11x?

the area cut from the sheet of wrapping paper
the area of the sheet of wrapping paper after being cut
the area of the sheet of wrapping paper before being cut
the width of the sheet of wrapping paper after being cut
Mathematics
2 answers:
user100 [1]3 years ago
4 0
<em>x</em>² represents the area of the original sheet of wrapping paper.  This would be a square that is <em>x</em> units long and <em>x</em> units wide.  11<em>x</em> would be the area of the section she cut off; she cut off 11 cm from the width, so the width of the piece cut off is 11, and the length of the piece she cut off is still <em>x.  </em>The area of a rectangle is given by width * length; in this case 11*<em>x</em> or 11<em>x</em>.
The expression she has, <em>x</em>² - 11<em>x</em>, represents the area of the sheet of wrapping paper after she's cut it.<em />
Anna [14]3 years ago
4 0

Answer:

The correct option is 1. It means 11x is the area cut from the sheet of wrapping paper.

Step-by-step explanation:

The shape of sheet is square.

Let  x represents the length, in centimeters, of the sheet of wrapping paper before being cut.

The area of a square is

A=a\times a

Where, a is side length.

The area of sheet before being cut is

A=x\times x=x^2

The width of the piece cut from the sheet is 11 and length is x. So, the area of piece is

A=x\times 11=11x

The remaining area of sheet is

A=\text{Area of sheet}-\text{Area of piece cut from the sheet}

A=x^2-11x

Therefore correct option is 1. It means 11x is the area cut from the sheet of wrapping paper.

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Tony sees an outfit that he
REY [17]

Answer:

He need 345 $

Step-by-step explanation:

Data :

Shirt = 50 $

Pant = 75 $

Shoes = 375 $

Now add them

50 + 75 + 375 = 500 $ value 1

He has 155 $  value 2

Subtrate value 2 from value 1

    500 - 155 = 345 $

7 0
2 years ago
Hey I need a step by step of this!!! Or can you just explain to me how to figure it out step by step!! either is fine
Umnica [9.8K]

Answer:

I believe the answer may be x= 24.5 I'm not certain though

Step-by-step explanation:

The angles inside the triangle must all add up to 180 so we can subtract 80 from 180 to get 98. Now I'm assuming the two undefined angles are equal because of the two angle bisectors that create the second triangle. If I'm correct in assuming that them we can divided 98 by 2 to get 49 which would be the measurement of both bottom angles. Since there's a line bisecting both of them we would then cut that number in half to get 24.5. I hope this helped, I'm not fully certain of this answer though.

4 0
3 years ago
Let logb A= 3; logb C = 2; logb D=5<br> What is the value of logb D^2/C^3A
Ne4ueva [31]

Answer:

The value of given log function is 1 .

Step-by-step explanation:

Given as :

Logb A = 3

Logb C = 2

Logb D = 5

<u>Now from log property </u>

if , Logb x = c    , then  x = b^{c}

So,

Logb A = 3 , then A =  b^{3}

Logb C = 2 , then C =  b^{2}

Logb D = 5 , then D =  b^{5}

Now, According to question

Logb\frac{D^{2}}{C^{3}A}

So, Logb\frac{(b^{5})^{2}}{(b^{2})^{3}\times b^{3}}

Or, Logb\frac{b^{10}}{b^{6}\times b^{3}}

or, Logb\frac{b^{10}}{b^{9}}

Now, since base same So,

log_{b}b^{10-9}

∴ log_{b}b^{1}

<u>Now log property </u>

log_{b}b = 1

Hence The value of given log function is 1 . answer

5 0
3 years ago
Surveyors wished to know the distance across a lake between A and B. They measured the distance from B to C as 100 m and the ang
kherson [118]

Answer:

<h3>AB ≈ 70m</h3>

Step-by-step explanation:

Check the attachment for the diagram.

You can see from the diagram that it is a right angled triangle with opposite side AB and adjacent side BC. Using SOH, CAH, TOA trig identity to get the length of AB. According to TOA;

tan 35° = opposite/adjacent

tan 35° = AB/BC

tan 35° = AB/100

AB = 100tan35°

AB = 100 * 0.7002

AB = 70.02m

Hence the distance across a lake between A and B is approximately 70m

5 0
3 years ago
−8x + 3y = 21 solve it
Nataly [62]
So first we have to subtract 3y from 21 cause the oppisit of addition which is subtraction so you get 18y when we divide that with -8y and get y=2.25y
6 0
4 years ago
Read 2 more answers
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