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4 years ago

Can you use the SAS Postulate, the AAS Theorem, or both to prove the triangles congruent?

Mathematics

1 answer:

nadezda [96]4 years ago

3 0

AAS because there’s a vertical angle

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Simplify each expression<br><br> 1. 5 + 3 (x - 5) + 7 <br><br> 2. 1/2+2/3(y- 6)

exis [7]

Answer:

3(x-1)

Step-by-step explanation:

12+3x-15

-3+3x

3(x-1)

8 0

3 years ago

Read 2 more answers

james cut three squares lasagnas so that each piece was 1/5 of the lasagnas. how many pieces did james cut the lasagna into?

uysha [10]

The answer is 15. Each one is 5 pieces and there are 3 of them. so 5 x 3 = 15

4 0

3 years ago

Read 2 more answers

Which of the following is the solution of 1/4 x+5=7

Inessa05 [86]

Given equation is , $\frac{1}{4}x + 5 = 7$

To find x, first add - 5 on both sides

$\frac{1}{4}x + 5 - 5 = 7 - 5$

$\frac{1}{4}x = 2$

Multiply both side by 4 to isolate x

$4\times \frac{1}{4} x + 5 = 2 \times 4$

$1\times x = 2\times 4$

Now to find x, divide both side by 1

$\frac{1x}{1}= \frac{8}{1}$

x = 8

So option 3 is the answer

3 0

4 years ago

A biologist wants to determine the effect of a new fertilizer on tomato plants. What is the best design for this study?

lara [203]

The best design for this study is to do an independent and dependent experiment of the outcomes from different types of soils for tomato plants.

4 0

3 years ago

How can I evaluate this question?

ohaa [14]

$\bf \left(x^2-\cfrac{2}{\sqrt{x}}+1 \right)(\sqrt[3]{x}+3x-4)\quad 
\begin{cases}
\frac{2}{\sqrt{x}}\implies \frac{2}{x^{\frac{1}{2}}}\implies 2x^{-\frac{1}{2}}\\\\
\sqrt[3]{x}\implies x^{\frac{1}{3}}
\end{cases}
\\\\\\
(x^2-2x^{-\frac{1}{2}}+1)(x^{\frac{1}{3}}+3x-4)$

$\bf \\\\\\
\begin{cases}
x^2\cdot x^{\frac{1}{3}}+3x^3-4x^2\\\\
-2x^{-\frac{1}{2}}\cdot x^{\frac{1}{3}}-2x^{-\frac{1}{2}}\cdot 3x+2x^{-\frac{1}{2}}\cdot 4\\\\
+x^{\frac{1}{3}}+3x-4
\end{cases}
\\\\\\ 
\begin{cases}
x^{2+\frac{1}{3}}+3x^3-4x^2\\\\
-2x^{-\frac{1}{2}+\frac{1}{3}}-6x^{-\frac{1}{2}+1}+8x^{-\frac{1}{2}}\\\\
+x^{\frac{1}{3}}+3x-4
\end{cases}$

$\bf x^{\frac{7}{3}}+3x^3-4x^2-2x^{-\frac{1}{6}}-6x^{\frac{1}{2}}+8x^{-\frac{1}{2}}+x^{\frac{1}{3}}+3x-4
\\\\\\
\sqrt[3]{x^7}+3x^3-4x^2-\cfrac{2}{x^{\frac{1}{6}}}-6\sqrt{x}+\cfrac{8}{x^{\frac{1}{2}}}+\sqrt[3]{x}+3x-4
\\\\\\
x^2\sqrt[3]{x}+3x^3-4x^2-\cfrac{2}{\sqrt[6]{x}}-6\sqrt{x}+\cfrac{8}{\sqrt{x}}+\sqrt[3]{x}+3x-4$

8 0

3 years ago