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MrMuchimi
3 years ago
6

Simplify

t=" {( - 1)}^{10} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
4 0
The answer is one, because 1 is a absolute value so 1 x 10 is 10
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A technology magazine finds data that suggests the prices of computers with a specific configuration follow an approximately nor
Lerok [7]

Answer:

-2.7

Step-by-step explanation:

i did it.

6 0
4 years ago
. Identify the like terms in the expression x + 2x + y + 1
torisob [31]

Answer:

The like terms are x + 2x which is 3x

and the rest you cant combine

Step-by-step explanation:

3 0
3 years ago
Which points lie on the line that passes through point P and is parallel to the given line? Select three options.
gulaghasi [49]

Answer:

So we have (-1,3), (-2,2) and (-5,-1).

Step-by-step explanation:

So we need to find the equation of the line that is parallel to the blue line going through point P.

The slope of the blue line (count the rise/run) is 1/1=1.

Parallel lines have the same slope.  

So y=mx+b is the slope-intercept form where m is the slope and b is the y-intercept.

So since the blue line has slope 1 and parallel lines have the same slope then the line going through point P will have slope 1 too.

Point P is actually the y-intercept of the line going through P.

So the equation that is parallel to the blue line going through point P is y=1x+4. b was 4 because it was the y-intercept.

You can also just write y=1x+4 as y=x+4.

Testing the points:

(-4,2)?

Does y=x+4 for this point?  2=-4+4 which gives us 2=0 so no for this point.

(-1,3)?

Does y=x+4 for this point?  3=-1+4 which gives us 3=3 so yes for this point.

(-2,2)?

Does y=x+4 for this point?  2=-2+4 which gives us 2=2 so yes for this point.

(4,2)?

Does y=x+4 for this point?  2=4+4 which gives us 2=8 so no for this point.

(-5,-1)?

Does y=x+4 for this point?  -1=-5+4 which gives -1=-1 so yes for this point.

So we have (-1,3), (-2,2) and (-5,-1).

5 0
4 years ago
Read 2 more answers
The difference between the roots of the quadratic equation x2+x+c=0 is 6. Find c.
NemiM [27]
We have that
x_{1} - x_{2} = 6
Let y be the first root, then y - 6 will be the second one. Since both roots make the quadratic equation equal to 0, we have that:
y^{2}  + y + c =  (y - 6)^{2}  + (y - 6) +c
Solve for y:
y^{2} +y +c = y^{2} - 12y + 36 + y - 6 +c \\ y + 12y - y = 30 \\ y =  \frac{5}{2}
Plug in y = 5/2 into original quadratic equation and solve for c:
(  \frac{5}{2}) ^{2} +  \frac{5}{2}  +c = 0 \\  c= - \frac{5}{2}  -  \frac{25}{4}  \\ c = - \frac{35}{4}
So, the answer is c = -35/4
6 0
4 years ago
I will give brainlist to who ever gets it right
ser-zykov [4K]

Answer:

2(j+2)

Step-by-step explanation:

Since 2 is the GCF, you should take out 2 to make the answer 2(j + 2).

5 0
3 years ago
Read 2 more answers
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