All categories

2 years ago

The question in picture attached

Mathematics

1 answer:

krek1111 [17]2 years ago

4 0

Need free pointtdsssss

You might be interested in

A cyclist going downhill is accelerating at 1.2 m/s2. If the final velocity of the cyclist is 16 m/s after 10 seconds, what is t

Mariana [72]

4 m / sec
Hope this helped

6 0

2 years ago

Read 2 more answers

I need help answering the question in the picture provided

adoni [48]

answer:

(a).

Equation of circle is x² + y² - 25 = 0

(b).

(-5, 0) » yes

(√7, 1) » no

(-3, √21) » no

(0, 7) » no

Step-by-step explanation:

(a).

If centred at origin, centre is (0, 0)

General equation of circle:

${ \boxed{ \bf{ {x}^{2} + {y}^{2} + 2gx + 2fy + c = 0}}}$

but g and f are 0:

${x}^{2} + {y}^{2} + c = 0 \\ but : \\ c = {g}^{2} + {f}^{2} - {r}^{2} \\ c = { - 25}$

8 0

3 years ago

3 equivalent ratios for 20/15

castortr0y [4]

4/3
40/30
60/45
Simply multiply or divide both the 20 and the 15 to get an equivalent ratio.

7 0

3 years ago

Read 2 more answers

BRAINLIESTTT What is the square root of 5?

butalik [34]

Answer:

2.2360679775

that's what I counted and got yep u know I was wrong.

5 0

2 years ago

Read 2 more answers

If triangle ABC defined by the coordinates A(1,1), B(9,1), C(1,9) is dilated by a scale factor of 1/2

alukav5142 [94]

Answer:

The transformed points of the triangle ABC are $A' (x,y) = \left( \frac{1}{2}, \frac{1}{2}\right)$ , $B'(x,y) = \left(\frac{9}{2}, \frac{1}{2} \right)$ , $C'(x,y) = \left(\frac{1}{2}, \frac{9}{2}\right)$

Step-by-step explanation:

The new points after applying the scale factor are, respectively:

$A' (x,y) = \frac{1}{2}\cdot (1,1)$

$A' (x,y) = \left( \frac{1}{2}, \frac{1}{2}\right)$

$B' (x,y) = \frac{1}{2}\cdot (9,1)$

$B'(x,y) = \left(\frac{9}{2}, \frac{1}{2} \right)$

$C'(x,y) = \frac{1}{2}\cdot (1,9)$

$C'(x,y) = \left(\frac{1}{2}, \frac{9}{2}\right)$

7 0

3 years ago