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lukranit [14]
3 years ago
15

Please help me answer these questions

Mathematics
1 answer:
mamaluj [8]3 years ago
7 0

Answer:

i dont undrstand

Step-by-step explanation:

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My brain stopped. Please help
Over [174]

Answer:

∠1 = 90°

∠2 = 66°

∠3 = 24°

∠4 = 24°

Step-by-step explanation:

Usually the diagonals of a rhombus bisect each other at right angles.

Thus; ∠1 = 90°

Since they bisect at right angles, then;

∠R1S = 90°

Now, sum of angles in a triangle is 180°

Thus;

66° + 90° + ∠4 = 180°

156 + ∠4 = 180

∠4 = 180 - 156

∠4 = 24°

Now, also in rhombus, diagonals bisect opposite angles.

Thus; ∠4 = ∠3

Thus, ∠3 = 24°

Similarly, the diagonal from R to T bisects both angles into 2 equal parts.

Thus; ∠2 = 66°

6 0
2 years ago
What is the ratio for 4, 8, 12, 14 (r)
olasank [31]

answer for this question is 2 is to 4 is to6 is to 7

7 0
2 years ago
The graph has y-intercept (0, 6) and contains the point (2, 1).
prisoha [69]

Answer:

5x + 2y = 12

Step-by-step explanation:

Direction factor = (2, 1) - (0, 6) = (2, -5)

So, normal factor = (5, 2)

Line: 5x + 2y = k

(0, 6) -> L: 0 + 12 = 12 = k

L: 5x + 2y = 12

5 0
3 years ago
Plz help 100 points!!!
Bad White [126]

(5) Angle ADC is the sum of angles ADB and BDC.

(6) Yes, because lines AG and EC form two pairs of vertical angles, including ADC and EDG, as well as ADE and CDG.

(7) Angle HJK is clearly a right angle, and a right angle has measure 90°.

7 0
2 years ago
Guys, Can you please help me with these questions
MakcuM [25]

Answer:

a) w^{13} x^{5} y^{6}

b) \frac{x}{3y^{6} }

Step-by-step explanation:

a) (w^{2} xy^{3} )^{2}(w^{3}x )^{3}

1. Distribute the second power (2) outside the first pair of parenthesis:

(w^{2(2)} x^{2} y^{3(2)} )

= w^{4} x^{2} y^{6} (w^{3}x )^{3}

2. Distribute the third power (3) outside the second pair of parenthesis:

(w^{3(3)} x^{3} )

= w^{4} x^{2} y^{6} w^{9} x^{3}

3. Combine like terms:

w^{13} x^{5} y^{6}

--------------------------------------------

b) \frac{2x^{2} y^{5} }{6xy^{11} }

1. Factor the number 6 (= 2 · 3):

\frac{2x^{2} y^{5} }{2(3)xy^{11} }

2. Cancel the common factor (2):

\frac{x^{2} y^{5} }{3xy^{11} }

3. Cancel out xy^{5} in the numerator an denominator:

\frac{x}{3y^{6} }

hope this helps!

4 0
2 years ago
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