Answer:
$10800
Step-by-step explanation:
Answer:
There is a 100% probability that the selected tick is also a carrier of Lyme disease.
Step-by-step explanation:
The problem states that:
Of the ticks that carry at least one of these diseases in fact carry both of them.
So, if a tick carries one of these diseases, there is a 100% probability that is carries another.
What is the probability that the selected tick is also a carrier of Lyme disease?
There is a 100% probability that the selected tick is also a carrier of Lyme disease.
Answer:
D. 1.2
Step-by-step explanation:
The sum of an arithmetic sequence is the product of the average term value and the number of terms.
The average term is often computed by averaging the first and last terms of the sequence. It can also be computed by averaging the middle two terms of the sequence (when there are an even number of terms, as here).
We are given a_13 is 1.9. We know that a_12 is 3.7 less, so is -1.8. Then the average of these two middle terms is ...
... (-1.8 + 1.9)/2 = 0.05
The product of this value and the number of terms (24) is ...
... 24·0.05 = 1.2 . . . . . the sum of 24 terms of the sequence
A≈173.82cm² that's the answer.
