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3 years ago

11

HELP ME HELP ME HELP ME

1 answer:

Tems11 [23]3 years ago

3 0

Answer:

nv dnvfjnvfnjnfxnbfndbnfjdnbfdnj

Step-by-step explanation:

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There are 70 students in the school band. 40% of them are sixth graders, 20% are seventh graders, and the rest are eighth grader

Anon25 [30]

Answer:

The number of students in the school band = 70

40% of students in the school band are sixth graders.

20% of students in the school band are seventh graders.

We have to find the number of band members that are sixth graders.

The number of sixth graders in school band are:

$40\% of 70$

$0.40 \times 70$

$28$

Therefore, there are 28 band members that are sixth graders.

4 0

4 years ago

Select the graph for the solution of the open sentence. Click until the correct graph appears. |x| > 3/2

Soloha48 [4]

ANSWER

See attachment

EXPLANATION

The given inequality is

$|x| \: > \: \frac{3}{2}$

This implies that,

$x\: > \: \frac{3}{2} \: or \: - x\: > \: \frac{3}{2}$

Multiply both sides of the second inequality by -1 and reverse the inequality sign.

$x\: > \: \frac{3}{2} \: or \: x\: < \: - \frac{3}{2}$

The graphical solution to this inequality is shown in the attachment.

7 0

3 years ago

What is 1-cos(6x)=___

FromTheMoon [43]

Answer:

2sin^2(3x)

Step-by-step explanation:

3 0

2 years ago

The researcher has limited resources. He sends 9 emails from a Latino name, and 14 emails from a non-Latino name. For the Latino

deff fn [24]

Answer: 38.41 minutes

Step-by-step explanation:

The standard error for the difference in means is given by :-

$SE.=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma^2_2}{n_2}}$

where , $\sigma_1$ = Standard deviation for sample 1.

$n_1$ = Size of sample 1.

$\sigma_2$ = Standard deviation for sample 2.

$n_2$ = Size of sample 2.

Let the sample of Latino name is first and non -Latino is second.

As per given , we have

$\sigma_1=82$

$n_1=9$

$\sigma_2=101$

$n_2=14$

The standard error for the difference in means will be :

$SE.=\sqrt{\dfrac{(82)^2}{9}+\dfrac{(101)^2}{14}}$

$SE.=\sqrt{\dfrac{6724}{9}+\dfrac{10201}{14}}$

$SE.=\sqrt{747.111111111+728.642857143}$

$SE.=\sqrt{1475.75396825}=38.4155433158\approx38.41$

Hence, the standard error for the difference in means =38.41 minutes

3 0

3 years ago

9/14 write as a fraction

Nina [5.8K]

Answer:

Hi. 9/14 is a fraction already. Maybe you meant decimal?

Step-by-step explanation:

7 0

3 years ago