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stich3 [128]
3 years ago
8

Please let me know what I could do

Mathematics
1 answer:
hjlf3 years ago
8 0

Answer:

7x³/10 - 7x² + 5x - 3/4

Step-by-step explanation:

The first step is to group the like terms and combine them. Once you do that, you should end up with 7x³/10 - 7x² + 5x + 1/4 - 1. When you combine -1 and 1/4, you should get -3/4. Afterwards, write the equation in standard form to get 7x³/10 - 7x² + 5x - 3/4. I hope this helps

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A rectangle has a perimeter of 84 meters and a length of 35 meters. What is the width of the rectangle?
BaLLatris [955]
To find the perimeter of a rectangle, we can use this formula: 2L + 2W
Where L is the length and W is the width.

We know the perimeter and we know the length and we want to find the width.
Substitute the values back into the formula.

2(35) + 2W = 84
70 + 2W = 84
2W = 14 <-- Subtract both sides by 70
W = 7 <-- Divide both sides by 2

So, width is 7 meters long.

8 0
3 years ago
Read 2 more answers
) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle
Fynjy0 [20]

The surface (call it S) is a triangle with vertices at the points

x=0,y=0\implies z=2\implies(0,0,2)

x=0,y=2\implies z=-2\implies(0,2,-2)

x=2,y=0\implies z=-8\implies(2,0,-8)

Parameterize S by

\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)

with 0\le u\le1 and 0\le v\le1. Take the normal vector to S to be

\vec s_v\times\vec s_u=(20v,8v,4v)

Then the flux of \vec F across S is

\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv

=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}

8 0
3 years ago
Max's grade on the first math exam was a 94. His grade on his seond math exam was an 89. What was the percent of change in Max's
Tom [10]

We are given that

Max's grade on the first math exam was a 94

so, first exam grade =94

His grade on his seond math exam was an 89

so, second exam grade =89

change in grade=(first exam grade)-(second exam grade)

change in grade=94-89

change in grade=5

Percentage = ( change in grade)/( first exam grade) *100

so, percentage is

=\frac{5}{94}\times 100

so,

the percent of change in Max's grade to the nearest whole percentage was 5%..........Answer



5 0
3 years ago
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trapecia [35]

Answer:

With probability you can multiply your chances in this case.

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Therefore it is a 1/12 chance to be both odd and greater than 4

8 0
3 years ago
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Single Factor ANOVA is a method we use when we want to compare a quantitative variable among more than two categories.
Goryan [66]

Answer:

The given statement is "True".

Step-by-step explanation:

A statistical analytical technique that divides the perceived aggregate unpredictability present throughout an information source even further into 2 components.

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If relevant information yet another category independent variable, as well as another quantifiable variable of interest, has been obtained, are using a single-way ANOVA.

Thus the above is the true answer.

3 0
3 years ago
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