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stich3 [128]
3 years ago
8

Please let me know what I could do

Mathematics
1 answer:
hjlf3 years ago
8 0

Answer:

7x³/10 - 7x² + 5x - 3/4

Step-by-step explanation:

The first step is to group the like terms and combine them. Once you do that, you should end up with 7x³/10 - 7x² + 5x + 1/4 - 1. When you combine -1 and 1/4, you should get -3/4. Afterwards, write the equation in standard form to get 7x³/10 - 7x² + 5x - 3/4. I hope this helps

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Simplify (11+4)x10+5
AURORKA [14]

Answer:

155

Step-by-step explanation:

= (15)x10+5

= 150+5

= 155

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4 years ago
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What is the approximate volume of a cylinder with a diameter of 14 meters and a height of 10 meters? Use 3.14 for pi.
WITCHER [35]
V = πr2<span>h

V = 3.14 x 7 x 7 x 10</span><span>

V = </span>1538.6 cubic meters.

Hope i become the brainliest.
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3 years ago
6. An ostrich cannot fly, but it is able to run fast. Suppose an ostrich runs east for 7.95 s and then runs 161 m south, so that
Liula [17]

Answer:

159 m

Step-by-step explanation:

From the information given:

It was stated that if the ostrich ran towards the east direction in 7.95 s, let say the distance from the starting point is O towards the east side E, let called the distance towards the east side to be OE.

Again, the ostrich then runs in the south direction for 161 m, let the distance be OS.

Also, let the magnitude of the resultant displacement between the east direction to the south direction be ES = 226m.

We are to find, the magnitude of the ostrich's eastward component.

i.e. The distance traveled from the center to the east direction within the time frame of 7.95 s.

Using the Pythagoras rule:

ES² = OE² + OS²

226² = OE² + 161²

226² -  161² = OE²

OE²  =  226² -  161²

OE²  = 51076 - 25921

OE²  =  51076 - 25921

OE²  =  25155

OE = \sqrt{25155}

OE =  158.60 m

OE ≅ 159 m

Thus, the magnitude of the ostrich's towards the eastward component. = 159 m.

4 0
3 years ago
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the answer is d.

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3 years ago
3. Find the height of a cylinder of volume 200 cm3 and radius 4 cm.
Mrrafil [7]

Answer:

h≈3.98cm this is the answer please mark me as a brainlist

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