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3 years ago

8

Please let me know what I could do

1 answer:

hjlf3 years ago

8 0

Answer:

7x³/10 - 7x² + 5x - 3/4

Step-by-step explanation:

The first step is to group the like terms and combine them. Once you do that, you should end up with 7x³/10 - 7x² + 5x + 1/4 - 1. When you combine -1 and 1/4, you should get -3/4. Afterwards, write the equation in standard form to get 7x³/10 - 7x² + 5x - 3/4. I hope this helps

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Find the solutions for a triangle with a = 16, c =12, and B = 63º.

maks197457 [2]

Answer:

b. A = 71.6°; C = 45.40°; b =15.0

Step-by-step explanation:

The missing values can be found with the help of the Law of Cosine and properties of triangles:

Side b (Law of Cosine)

$b = \sqrt{a^{2}+c^{2}-2\cdot a \cdot c \cdot \cos B}$

$b = \sqrt{16^{2}+12^{2}-2\cdot (16)\cdot (12) \cdot \cos 63^{\circ}}$

$b \approx 15.022$

Angle A (Law of Cosine)

$\cos A = -\frac{a^{2} - b^{2}-c^{2}}{2\cdot b \cdot c}$

$\cos A = - \frac{16^{2}-15.022^{2}-12^{2}}{2\cdot (15.022)\cdot (12)}$

$\cos A = 0.315$

$A= \cos^{-1} 0.315$

$A \approx 71.639^{\circ}$

Angle C (Sum of internal angles in triangles)

$C = 180^{\circ} - 63^{\circ} - 71.639^{\circ}$

$C = 45.361^{\circ}$

Hence, the right answer is B.

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