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andre [41]
3 years ago
6

Gillian purchased 25 books at the library book sale. Each hardcover book cost $1.50, and each paperback book cost $0.50. Gillian

spent a total of $26.50. The book costs can be represented by the system of equations below.
h + p = 25
1.50h + 0.50p = 26.50
How many paperback books did Gillian buy?
Mathematics
2 answers:
stepan [7]3 years ago
3 0
25-14=11 and 26.5-21=5.5
11 paperback books
madam [21]3 years ago
3 0

Answer:

Number of books did Gillian buy is 11.

Step-by-step explanation:    

Given : Gillian purchased 25 books at the library book sale. Each hardcover book cost $1.50, and each paperback book cost $0.50. Gillian spent a total of $26.50.

To find : How many paperback books did Gillian buy?

Solution :

The book costs can be represented by the system of equations below.

h+p= 25 ......(1)

1.50 h + 0.50 p = 26.50 ......(2)

Solving the system of equations by substitution method

Substitute h=25-p from (1) into (2)

1.50(25-p) + 0.50 p = 26.50

37.5-1.50p + 0.50 p = 26.50

p = 11

Substitute back in equation (1),

h+11= 25

h=14

i.e. there are 11 paperback books and 14 hardcover books.

Therefore, Number of books did Gillian buy is 11.

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earnstyle [38]

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<em><u>Solution:</u></em>

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To find: Minutes required for 6 people to paint 7 walls

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\frac{M_1D_1H_1}{W_1} = \frac{M_2D_2H_2}{W_2}

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H = Number of hours per day

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Here in this sum,

<em><u>54 minutes for 4 people to paint 6 walls</u></em>

H_1 = 54 minutes ; M_1 = 4 people ; W_1 = 6 walls

<em><u>Minutes required for 6 people to paint 7 walls</u></em>

H_2 = ? ; M_2 = 6 people ; W_2 = 7 walls

<em><u>Substituting the values in formula, we get</u></em>

\frac{54 \times 4}{6} = \frac{H_2 \times 6}{7}\\\\9 \times 4 = \frac{H_2 \times 6}{7}\\\\H_2 = \frac{36 \times 7}{6}\\\\H_2 = 42

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7 0
3 years ago
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Sladkaya [172]

Answer:

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Step-by-step explanation:

5,11,19,29

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--------------------------------

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