How do i solve s^2=81

Taylor wants to center a 3.5 inch picture on a piece of paper that is 12 inches wide How

AVprozaik [17]

Answer:

The picture is 4.25 inches from the side of the paper

Step-by-step explanation:

- Taylor wants to center a 3.5 inch picture on a piece of paper that is

12 inches wide

- Lets think about that he want to put the picture in the center of the

paper, then divide the length of the paper into two equal parts and the

picture into two equal part

∵ The width of the paper is 12 inches

∵ 12 ÷ 2 = 6 inches

∵ The width of the picture is 3.5 inches

∵ 3.5 ÷ 2 = 1.75

- Now lets subtract from 6 inches (half paper) 1.75 inches (half picture)

to find the distance between the side of the paper and the picture

∵ 6 - 1.75 = 4.25

∴ The distance from the side of the paper to the picture is 4.25 inches

* <em>The picture is 4.25 inches from the side of the paper</em>

* Look to attached figure for more understand

7 0

3 years ago

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A number added to 3 is equal to negative 5, find the number

anzhelika [568]

Answer:

-8

Step-by-step explanation:

An equation at represents this situation is:

-5 = 3 + x

Find x by;

-5 - 3 = -8

So x is -8:

-5 = 3 + -8 (TRUE)

Hope this helps

6 0

3 years ago

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Simplify. 2³+4⋅8 please I beg you

dalvyx [7]

2^3=2*2*2
2*2*2+4*8
8+32
=> 40

8 0

3 years ago

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Question : In the given figure , ∆ APB and ∆ AQC are equilateral triangles. Prove that PC = BQ.

lorasvet [3.4K]

Answer:

See Below.

Step-by-step explanation:

We are given that ΔAPB and ΔAQC are equilateral triangles.

And we want to prove that PC = BQ.

Since ΔAPB and ΔAQC are equilateral triangles, this means that:

$PA\cong AB\cong BP\text{ and } QA\cong AC\cong CQ$

Likewise:

$\angle P\cong \angle PAB\cong \angle ABP\cong Q\cong \angle QAC\cong\angle ACQ$

Since they all measure 60°.

Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

$m\angle PAC=m\angle PAB+m\angle BAC$

Likewise:

$m\angle QAB=m\angle QAC+m\angle BAC$

Since ∠QAC ≅ ∠PAB:

$m\angle PAC=m\angle QAC+m\angle BAC$

And by substitution:

$m\angle PAC=m\angle QAB$

Thus:

$\angle PAC\cong \angle QAB$

Then by SAS Congruence:

$\Delta PAC\cong \Delta BAQ$

And by CPCTC:

$PC\cong BQ$

5 0

3 years ago

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One study reports that 34% of newly hired MBAs are confronted with unethical business practices during their first year of empl

MaRussiya [10]

Answer:

$z=\frac{0.28 -0.34}{\sqrt{\frac{0.34(1-0.34)}{116}}}=-1.364$

$p_v =2*P(Z$

The p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIl to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace is not significant different from 0.34.

Step-by-step explanation:

1) Data given and notation

n=116 represent the random sample taken

X represent the number graduates from the previous year claim to have encountered unethical business practices in the workplace

$\hat p=0.28$ estimated proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace

$p_o=0.34$ is the value that we want to test

$\alpha=0.05$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion is 0.34 or no.:

Null hypothesis: $p=0.34$

Alternative hypothesis: $p \neq 0.34$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.28 -0.34}{\sqrt{\frac{0.34(1-0.34)}{116}}}=-1.364$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(Z$

The p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIl to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace is not significant different from 0.34.

5 0

4 years ago