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3 years ago

Twice a number decreased by one equals the same number added to two

Mathematics

1 answer:

nignag [31]3 years ago

8 0

Answer:

Step-by-step explanation:

3x3=6-1=5

3+2=5

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Find the measure of the supplement of a 95 degree angle

maksim [4K]

Answer: it is 85 degrees

Step-by-step explanation:

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4 years ago

Which expression gives the best estimate of 30 percent of 61?

RSB [31]

Answer:

The answer is A

Step-by-step explanation:

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3 years ago

Express 5×-4y=20 in the form a×+by+c=0and write the value of a,band c<br><br>

finlep [7]

Answer:

a = 5

b = -4

c = -20

Step-by-step explanation:

Here, we want to express the given equation in the following form;

So we can have this as;

5x-4y-20 = 0

That means we have;

a as 5

b as -4

and c as -20

4 0

3 years ago

I need help with this math problem.

katrin [286]

Answer:

The answer to your question is s = 399.5 m

Step-by-step explanation:

Formula

$s = \sqrt{\frac{3V}{h}}$

Data

V = 7 500 000 m³

h = 141 m

Substitution

$s = \sqrt{\frac{3(7500000)}{141}}$

$s = \sqrt{\frac{22500000}{141}}$

$s = \sqrt{159574.47}$

s = 399.46 meters ≈ 399.5 meters

5 0

3 years ago

Read 2 more answers

A) how many men have a waist measurement of more than 85 cm

KATRIN_1 [288]

Answer:

(a)29

(b)91cm

Step-by-step explanation:

(a)From the graph, 11 men have a waist measurement of 85cm and below.

Since the cumulative frequency is 40

Number of men who have a waist measurement of more than 85 cm

$=40-11\\=29$

(b)Median

$\text{Median}=\dfrac{N}{2}\\N=40\\Median=\dfrac{40}{2}=20th$ item$

Tracing 20 from the y-axis to the x-axis, the median waist measurement is 91cm.

(c)Interquartile Range

Interquartile Range = $Q_3-Q_1$

$Q_1=\dfrac{N}{4}=\dfrac{40}{4}=10th$ item$

From the graph, at y=10, x=84 cm

$Q_3=\dfrac{3N}{4}=\dfrac{3*40}{4}=30th$ item$

From the graph, at y=30, x=97 cm

Therefore:

Interquartile Range=97-84=13cm

5 0

3 years ago