The software that has no restrictions from copyright holder regarding modification of the software's internal and its redistribution is called an Open source software. They are being provided for use and redistribution for free, with no cost. They can be easily downloaded on the Internet.
Answer:
#include <iostream>
#include <array>
using namespace std;
bool isPalindrome(string str)
{
int length = str.length();
for (int i = 0; i < length / 2; i++)
if (toupper(str[i]) != toupper(str[length - 1 - i]))
return false;
return true;
}
int main()
{
array<string, 6> tests = { "madam", "abba", "22", "67876", "444244", "trymEuemYRT" };
for (auto test : tests) {
cout << test << " is " << (isPalindrome(test) ? "" : "NOT ") << "a palindrome.\n";
}
}
Explanation:
The toupper() addition forces characters to uppercase, thereby making the comparison case insensitive.
Answer:
The program in Python is as follows:
num1 = int(input())
num2 = int(input())
if num1 >=0 and num2 >= 0:
print(num1+num2)
elif num1 <0 and num2 < 0:
print(num1*num2)
else:
if num1>=0:
print(num1**2)
else:
print(num2**2)
Explanation:
This gets input for both numbers
num1 = int(input())
num2 = int(input())
If both are positive, the sum is calculated and printed
<em>if num1 >=0 and num2 >= 0:</em>
<em> print(num1+num2)</em>
If both are negative, the products is calculated and printed
<em>elif num1 <0 and num2 < 0:</em>
<em> print(num1*num2)</em>
If only one of them is positive
else:
Calculate and print the square of num1 if positive
<em> if num1>=0:</em>
<em> print(num1**2)</em>
Calculate and print the square of num2 if positive
<em> else:</em>
<em> print(num2**2)</em>
