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KiRa [710]
3 years ago
13

Observe the following statements and decide whether the variable result’s value is TRUE or FALSE.

Computers and Technology
1 answer:
devlian [24]3 years ago
5 0

Answer:

    result 1 = false;

     result 2 = true;      

Explanation:

result 1 = (43 < -77 && 1! = 10)

            43 < -77 = false

             1 != 10 = true

for any false && true logical operator, it returns false

    result 1 = false;

 false = 90 < -77 || -1 < 43

              90 < -77 = false

                -1 < 43 = true

for any false || true logical operator, it returns true

  result 2 = true;      

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ycow [4]

Answer:

Promiscuous mode

Explanation:

You decide to use a packet sniffer to identify the type of traffic sent to a router. You run the packet sniffing software on a device connected to the same hub that is connected to the router. When you run the software, you only see frames addresse…

✓ Promiscuous mode

7 0
2 years ago
Write the following function without using the C++ string class or any functions in the standard library, including strlen(). Yo
dolphi86 [110]

Answer:

The function in C++ is as follows

int chkInd(string str1, string str2){    

int lenstr1=0;

while(str1[lenstr1] != '\0'){  lenstr1++;  }

int index = 0; int retIndex=0;

for(int i=lenstr1-1;i>=0; i--){

   while (str2[index] != '\0'){

       if (str1[i] == str2[index]){

           retIndex=1;

           break;         }

       else{   retIndex=0;      }

  index++;    }

  if (retIndex == 0){   return i;   }else{return -1;}}

}

Explanation:

This defines the function

int chkInd(string str1, string str2){    

First, the length of str1 is initialized to 0

int lenstr1=0;

The following loop then calculates the length of str1

while(str1[lenstr1] != '\0'){  lenstr1++;  }

This initializes the current index and the returned index to 0

int index = 0; int retIndex=0;

This iterates through str1

for(int i=lenstr1-1;i>=0; i--){

This loop is repeated while there are characters in str2

   while (str2[index] != '\0'){

If current element of str2 and str1 are the same

       if (str1[i] == str2[index]){

Set the returned index to 1

           retIndex=1;

Then exit the loop

           break;         }

If otherwise, set the returned index to 0

       else{   retIndex=0;      }

Increase index by 1

  index++;    }

This returns the calculated returned index; if no matching is found, it returns -1

  if (retIndex == 0){   return i;   }else{return -1;}}

}

4 0
3 years ago
- Create a Java program in both Windows and Ubuntu using any of their Editors *** DO NOT USE IDE'S SUCH AS ECLIPSE, NETBEANS, ET
Marat540 [252]

Answer:

Following are the code to this question:

public class ArrayMath//defining a class ArrayMath

{

public static void main(String[] args) //defining main method

{

int x[][]=new int[10][10]; //defining a 2D array  

arrays(x);//calling a method arrays by passing an array

}

private static void arrays(int[][] x)//defining a method arrays

{

int odd_column_sum=0,sum_of_Elements=0,i,j,even=1;//defining integer variable  

for(i=0;i<x.length;i++)//defining loop for columns  

{

for(j=0;j<x[0].length;j++)//defining loop for rows

{

x[i][j]=i*j;//multiply the i and j value atore in array

}

}

System.out.println("::The 2D array :: ");//print message

for(i=0;i<x.length;i++)//defining loop for columns

{

System.out.print("\t");//use print method for line space and line break  

for(j=0;j<x[0].length;j++)//defining loop for rows

{

System.out.printf("%d\t",x[i][j]); //print array values

}

System.out.println( );//print for line break

}

for(i=0;i<x.length;i++) //defining loop for Columns

{

for(j=0;j<x[0].length;j++) //defining loop for rows

{

if(even%2!=0)//defining if block for check odd number condition

{

odd_column_sum+=x[j][i];//add odd number of array

}

sum_of_Elements+=x[i][j];//add even number of array

}

even++;//increment even variable value by 1

}

System.out.println("The sum of Odd Columns:"+odd_column_sum);//print odd_column_sum value

System.out.println("The array elements :"+sum_of_Elements);//print sum_of_Elements value

}

}

Output:

please find attached file.

Explanation:

In the above-given code, a class "ArrayMath" is defined, inside the class the main method is declared, which define a 2D array "x", this stores 10 columns and 10 rows and at the last, we call the arrays method by passing an array as a variable.

In the arrays method, integer variable, "odd_column_sum, sum_of_Elements, i, j, and even" is defined, in which variable "i and j" is used in the loop for calculating value, even is used to check odd column and then store its value in the "odd_column_sum" variable, and add whole element value is added into the "sum_of_Elements" variable.

8 0
3 years ago
Early word processors ran on devices that look like digital
S_A_V [24]

Answer:

True

Explanation:

The word processor used to be the only office machine in the year 1960s, that combined the keyboard text-entry and various printing functions of an electric typewriter with the recording memory. And this recording unit was a tape or a floppy disk, with the simplest of processor applied for text editing. Hence, the above statement that the early word processors ran on the devices that look like digital is true.

6 0
3 years ago
Read 2 more answers
Meg[] elements = {new Lois(), new Stewie(), new Meg(), new Brian()}; for (int i =0; i
Stells [14]

Complete question is attached as snapshot.

Answer:

This will result in a compilation error.

Here's the inheritance hierarchy:

Meg -> Lois -> Brian -> Stewie

Now Meg has 2 public Fxns, a() and toString().

Lois inherits from Meg and all its public functions as well but, overrides the a() fxn of its super class.

So finally Lois has fxns a(), b() and toString().

Brian extends Lois and inherits all the above listed fxns of Lois, but overrides the b() and toString() fxns.

Stewie extends Brian and inherits all the fxns of Brian, but overrides the a() and toString() fxns.

In the Main driver fxn, we call a() and b() methods of all these classes but, the base class Meg has no b() and it is not extending any class so its not available in its scope.

This results in a compilation error.

Explanation:

7 0
3 years ago
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