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Salsk061 [2.6K]
3 years ago
9

Can someone help me with these?? I am really confused

Mathematics
1 answer:
liraira [26]3 years ago
6 0
Question4: C, question 5: A
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In the figure below, the following is true: angle ABD is congruent to angle CDB and angle DBC is congruent to angle BDA. How can
sergiy2304 [10]
<span>triangle ABD and the triangle CDB are similar 
the options are </span><span>ASA and CPCTC</span>
7 0
4 years ago
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Could somebody help me please
pantera1 [17]

Answer:

its 7

Step-by-step explanation:

7 0
3 years ago
Find the height of a right cylinder with surface area 160pie square units and radius 5 units
jenyasd209 [6]

Given:

Radius of a cylinder = 5 units.

Surface area of the cylinder = 160\pi

To find:

The height of the right cylinder.

Solution:

Surface area of a cylinder is:

A=2\pi rh+2\pi r^2

Where, r is radius and h is the height of the cylinder.

Putting r=5, A=160\pi in the above formula, we get

160\pi =2\pi (5)(h)+2\pi (5)^2

160\pi =10\pi h+2\pi (25)

160\pi =10\pi h+50\pi

Subtract 50\pi from both sides.

160\pi -50\pi=10\pi h

110\pi=10\pi h

Divide both sides by 10\pi.

\dfrac{110\pi}{10\pi}=h

11=h

Therefore, the height of the cylinder is 11 units.

8 0
3 years ago
Which fraction is bigger 2/3 or 2/8
igomit [66]
2/3 = 0.6666 
2/8 = 0.25 

Obviously, 2/3 is bigger than 2/8. 
6 0
3 years ago
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Which sequence is modeled by the graph below? Points: (2,8) (3,4) (4,2) (5,1)
asambeis [7]

Answer:

a_n=16 \cdot (\frac{1}{2})^{n-1}

Step-by-step explanation:

This sequence is geometric because while x is going up by 1, the y sequence has a common ratio.

That is, term/previous equals same number per consecutive y terms.

So 1/2=2/4=4/8 is the common ratio.

The first term is when x=1. We can find this y by figuring out what we can multiply to our common ratio, 1/2, to get the next term,8.

Since 8(2)=16, then the first term is 16.

In general,

y=a_1 \cdot (r)^{x-1}

Or if preferred:

a_n=a_1 \cdot (r)^{n-1}

where a_1 is first term and r is common ratio.

Plug in information:

a_n=16 \cdot (\frac{1}{2})^{n-1}

7 0
3 years ago
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