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lana [24]
3 years ago
8

What is the length of BC​

Mathematics
1 answer:
elena55 [62]3 years ago
3 0

Answer:

BC = 2

Step-by-step explanation:

We first need to use triangle BAD to find BD,

BD is the hypotenuse, so use pythagorean theorem...

      (√23)² + (√13)² = (BD)²

            23 + 13 = (BD)²

               36 = (BD)²

                  6 = BD

Now BD is the hypotenuse of triangle BCD, so use pythagorean theorem agian to find BC

     (4√2)² + (BC)² = 6²

            32 + (BC)² = 36

                   (BC)² = 4

                        BC = 2

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Answer:

The answer is 1

Step-by-step explanation:

i) \dfrac{(5\frac{4}{45} -4 \frac{1}{6})\div5\frac{8}{15}   }{(4\frac{2}{3} +0.75)\times3\frac{9}{13}}\times34\frac{2}{7} + \frac{0.3\div0.01}{70} + \frac{2}{7}

ii)\dfrac{(\frac{229}{45} -\frac{25}{6})\div\frac{83}{15}   }{(\frac{14}{3} +\frac{3}{4})\times\frac{48}{13}}\times\frac{240}{7} + \frac{30}{70} + \frac{2}{7}

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iii)(\dfrac{(\frac{458}{90} -\frac{375}{90})\times\frac{15}{83}   }{(\frac{56}{12} +\frac{9}{12})\times\frac{48}{13}}\times\frac{240}{7}) + \frac{30}{70} + \frac{2}{7}

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iv) (\dfrac{(\frac{83}{90})\times\frac{15}{83}   }{(\dfrac{65}{12} )\times\dfrac{48}{13}}\times\dfrac{240}{7}) + \dfrac{30}{70} + \dfrac{2}{7}

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v)(\dfrac{(\frac{1}{6})   }{(5\times4)}\times\dfrac{240}{7}) + \dfrac{30}{70} + \dfrac{20}{70}

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vi)(\dfrac{1}{(6\times5\times4)}\times\dfrac{240}{7}) + \dfrac{50}{70}

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vii)(\dfrac{1}{120}\times\dfrac{240}{7}) + \dfrac{50}{70}

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Next
AveGali [126]

Answer:

C. Robbie's glider

Step-by-step explanation:

P.S -The exact question is -

Given - Melissa and Robbie are flying remote control gliders.

The altitude of Melissa's glider, h(s), in feet, is modeled by this function, where sis time, in seconds, after launch.

m(s) = 0.4(s³ - 11s² + 31s – 1)

The altitude of Robbie's glider is modeled by function r, where sis time, in seconds, after launch.

To find - Which glider reaches the greater maximum altitude in the first 6 seconds after launch?

A. Neither glider reaches a maximum altitude on the given interval.

В. Melissa's glider

C. Robbie's glider

D. Both gliders reach the same altitude on the given interval.

Proof -

At t = 6 sec,

Melisa glider is

h(6) = 0.4((0.6)³ - 11(0.6)² + 31(0.6) – 1)

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⇒h(6) = 5.5424

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At t = 6 seconds, Melissa glider is at the altitude of 5.54 feet

Now,

From the figure, we can see that,

At t = 6 seconds, Robbie's glider is approximately at an altitude of 13 feet

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As 13 > 5.5

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Robbie's glider is at maximum height in 6 seconds after the launch.

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The correct option is - C. Robbie's glider

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