Yes it is the right answer .-.
Answer:
- c(n) = 320·0.96^n
- 28 years
Step-by-step explanation:
Each year, the class size is multiplied by 1 - 4% = 96% = 0.96. After n years, it has been multiplied by that number n times. Repeated multiplication is signified using an exponent.
Class size (c) can be modeled by ...
c(n) = 320·0.96^n
__
You want to find n such that c(n) = 100. Put in that value and solve.
100 = 320·0.96^n
100/320 = 0.96^n . . . . . . . divide by 320
log(100/320) = n·log(0.96) . . . . . . . take logs
log(100/320)/log(0.96) = n ≈ 28.4932
In about 28 years, the class will have 100 students.
11 is the answer to your question
Answer:
(b) (18, 27), because the rate of change of the function is 4/3
Step-by-step explanation:
just took the test mah peeps;)
