Answer:
its d
Step-by-step explanation:
just took the test
The slope is negative, so the slope is negative. Using the rise over run formula, the slope of the line should be -1.
Ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating
y=-2x^2-12x-28
a=-2
b=-12
xvalue of vertex is -(-12)/(2*-2)=12/-4=-3
x value of vertex is -3
plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10
yvalue is -10
x value is -3
vertex is (-3,-10)
4|y-9| > 36
Two equations:
4(y-9)>36 then y-9>8 then y>17
4(y-9)<-36 then y-9<-8 then y<1
So, the solution is y<1 or y>17
0.5|x+2| > 6
Two equations:
0.5(x+2) > 6 then 0.5x+1>6 then x>10
0.5(x+2) < -6 then 0.5x+1<-6 then x<-14
So, the solution is: x<-14 or x>10
