In any given right triangle, the Pythagorean Theorem can be used to show that it is a right triangle.
The Pythagorean Theorem is a^2+b^2=c^2. In a right triangle, a and b would be the shorter legs of the triangle, while c would be the hypotenuse.
So for this problem, you would plug in the numbers in the order that they are listed to see if it is a right triangle.
F would be: 2^2+4^2=7^2. In this case, the sides are not equal.
G would be: 6^2+8^2=10^2. In this case, 100=100. So this is a right triangle.
H would be: 4^2+9^2=12^2. The sides are not equal.
J would be: 5^2+10^2=15^2. The sides are not equal.
Your answer would be G, since the sides are equal. Hope this helps! :)
Given: <span>2x-y-3=0.
find </span>equation for the line perpendicular to the given line that goes through the given point:<span>
(2;-1)koord of direction vector (i`m not know how it is called at you, because i'm from russia)</span><span>
=> (x-0)/2=(y-4)/-1 (</span>canonical <span>equation)
=>x+2y-8=0(general </span><span>equation)
</span>
<span>further:
{x+2y-8=0
{2x-y-3 =0 => y=13/5 x=14/5
(14/5; 13/5) - koord point on line
</span>|dist|=sqrt( (14/5-0)^2 + (13/5-4)^2 ) = sqtr(7.72) = 2.78
Удачи!
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</span>
Answer:
70
Step-by-step explanation:
Finding the common denominator is really just finding the gcf of 7 and 10. The gcf of 7 and 10 is 70. So the common denominator is 70.
Series = <span>{2, 5 ,6, 7, 15, 16, 17}
Here, Median = 7
Then Q3 = </span><span>{15, 16, 17}
Median of Q3 = 16
In short, Your Answer would be: 16
Hope this helps!</span>
Yes, this is a polynomial. It is an expression containing variables raised to a real number.
In this case, the variables are being raised to the power of one.
The degree of this polynomial, thus, is one.