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siniylev [52]
4 years ago
7

Not every straight line will pass the vertical line test. What is the only type

Mathematics
1 answer:
Art [367]4 years ago
8 0
<h3>Answer: B) vertical line</h3>

A vertical line has all points with the same x coordinate, but infinitely many different y coordinates. It inherently fails the vertical line test because we can pass a single straight line through more than one point on the function curve.

Put another way, the input is a single value but there's infinitely many outputs. A function must have each input produce exactly one output. This is of course only when the input is in the domain.

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Estimate the value of 48 square root to the nearest tenth.​
Sati [7]

Answer:

Square Root of 48 to the nearest tenth, means to calculate the square root of 48 where the answer should only have one number after the decimal point. To check that the answer is correct, use your calculator to confirm that 6.92 is about 48.

Step-by-step explanation:

There ya gooooo :)

4 0
3 years ago
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2.3.4 practice modeling graphs of functions
skad [1K]

Answer: 29?

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Step-by-step explanation:

5 0
3 years ago
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Answer:A=A

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Step-by-step explanation:

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4 years ago
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Answer:

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3 years ago
Find the sum of the equation
stealth61 [152]

Answer:

\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}

Step-by-step explanation:

1)  Rewrite {y}^{2}-2y+1y  in the form{a}^{2}-2ab+{b}^{2}, where a = y and b = 1.

\frac{y}{{y}^{2}-2(y)(1)+{1}^{2}}+\frac{6}{{y}^{2}+6y-7}

2)  Use Square of Difference: {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}.

\frac{y}{{(y-1)}^{2}}+\frac{6}{{y}^{2}+6y-7}

3)  Factor {y}^{2}+6y-7.

1 - Ask: Which two numbers add up to 6 and multiply to -7?

-1 and 7

2 - Rewrite the expression using the above.

(y-1)(y-7)

Outcome/Result: \frac{y}{(y-1)^2} +\frac{6}{(y-1)(y+7)}

4) Rewrite the expression with a common denominator.

\frac{y(y+7)+6(y-1)}{{(y-1)}^{2}(y+7)}

5)  Expand.

\frac{{y}^{2}+7y+6y-6}{{(y-1)}^{2}(y+7)}

6) Collect like terms.

\frac{{y}^{2}+(7y+6y)-6}{{(y-1)}^{2}(y+7)}

7) Simplify  {y}^{2}+(7y+6y)-6y  to  {y}^{2}+13y-6y

\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}

5 0
2 years ago
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