At the end of three days,
% of the original amount of liquid remains in Kyle's container .
<u>Step-by-step explanation:</u>
Here we have , Every day 10% of the liquid present in the morning in Kyle's open container will evaporate. At the end of three days, We need to find what percent of the original amount of liquid remains in Kyle's container . Let's find out:
Let's suppose initially we have 100% of liquid present so ,
<u>At day 1:</u>
10% of the liquid present(100%) in the morning in Kyle's open container will evaporate , So left is :
⇒ ![100- \frac{100(10)}{100}](https://tex.z-dn.net/?f=100-%20%5Cfrac%7B100%2810%29%7D%7B100%7D)
⇒ ![100-10](https://tex.z-dn.net/?f=100-10)
⇒
%
<u>At day 2:</u>
10% of the liquid present(90%) in the morning in Kyle's open container will evaporate , So left is :
⇒ ![90- \frac{90(10)}{100}](https://tex.z-dn.net/?f=90-%20%5Cfrac%7B90%2810%29%7D%7B100%7D)
⇒ ![90-9](https://tex.z-dn.net/?f=90-9)
⇒
%
<u>At day 3:</u>
10% of the liquid present(81%) in the morning in Kyle's open container will evaporate , So left is :
⇒ ![81- \frac{81(10)}{100}](https://tex.z-dn.net/?f=81-%20%5Cfrac%7B81%2810%29%7D%7B100%7D)
⇒ ![81-8.1](https://tex.z-dn.net/?f=81-8.1)
⇒
%
Therefore , At the end of three days,
% of the original amount of liquid remains in Kyle's container .
Answer:
x = 9. Rearrange variables to the left side of the equation: - x = - 5 - 4
Calculate the sum or difference: x=9
Step-by-step explanation:
Answer:
FOURTH ONE DOWN
Step-by-step explanation:
Basically the the format is (vertical / horizontal), so CB and AD are both gonna be denominators (the bottom of the fraction).
** also next time please take a better picture i had to squint my eyes so hard **
Answer:
0.00000763
Step-by-step explanation:
7 accounts for 1 place
6 - 1 = 5, therefore 5 0s after the decimal point
Did you add the picture of the table? I do not see it :(