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masha68 [24]
3 years ago
8

You randomly draw a marble from a bag of marbles that contains 8 blue marbles, 5 green marbles, and 8 red marbles. what is p(dra

w a blue or red marble)

Mathematics
2 answers:
JulsSmile [24]3 years ago
6 0

Answer:

P( blue or red ) =  \frac{16}{21}.

Step-by-step explanation:

Given : You randomly draw a marble from a bag of marbles that contains 8 blue marbles, 5 green marbles, and 8 red marbles.

To find : what is p(draw a blue or red marble).

Solution : We have given that

A beg contain  blue  marble = 8 .

Green marble = 5.

Red marble = 8 .

Total marble = 8 + 5 + 8 = 21.

Probability = \frac{Favpurable\ outcome}{Total\ outcome}.

Probability of draw blue = \frac{8}{21}.

Probability of draw red = \frac{8}{21}.

P( blue or red ) = \frac{8}{21} + \frac{8}{21}.

P( blue or red ) =  \frac{16}{21}.

Therefore, P( blue or red ) =  \frac{16}{21}.

LUCKY_DIMON [66]3 years ago
5 0
Hope this helps you :)

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