Question

You randomly draw a marble from a bag of marbles that contains 8 blue marbles, 5 green marbles, and 8 red marbles. what is p(draw a blue or red marble)

Answer 1

Answer:

P( blue or red ) =  $\frac{16}{21}$.

Step-by-step explanation:

Given : You randomly draw a marble from a bag of marbles that contains 8 blue marbles, 5 green marbles, and 8 red marbles.

To find : what is p(draw a blue or red marble).

Solution : We have given that

A beg contain  blue  marble = 8 .

Green marble = 5.

Red marble = 8 .

Total marble = 8 + 5 + 8 = 21.

Probability = $\frac{Favpurable\ outcome}{Total\ outcome}$.

Probability of draw blue = $\frac{8}{21}$.

Probability of draw red = $\frac{8}{21}$.

P( blue or red ) = $\frac{8}{21}$ + $\frac{8}{21}$.

P( blue or red ) =  $\frac{16}{21}$.

Therefore, P( blue or red ) =  $\frac{16}{21}$.

Answer 2

Hope this helps you :)