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ICE Princess25 [194]
2 years ago
13

Help me please Picture at the below

Mathematics
1 answer:
astra-53 [7]2 years ago
4 0

a=-2, b=3, c=-4, d=5

 abc-d

abc means multiply those 3 together

 so -2 x 3 x -4 = 24

24-5 = 19

answer is 19

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Suppose there are two types of tickets to a show: advance and same day. The combined cost of one advance ticket and one same day
Debora [2.8K]

Answer:

Answer = $30.00 advanced and $36.00 same day.

Step-by-step explanation: We can replace 20:40 ratio.

30 x 20 and 70 x 20 = 600+ 800 =3/5  to find 2/4 = 12/20 finds 10/20 through HCF and hereafter we have one ticket is 1/6 more. So if 60 tickets were sold for 2000 then $33.33 would be the average and if one was 1/6 more than the other it is 0.5/6 higher than 33.33 =2.66 more = £36 for All day and £30 for Advanced tickets. 36 x 20 = $600  and 36 x 40 =$1400. We know its $30 as we can double check its ratio after. 20:40 is 1/2 but then take off $3 each side to balance back to find $60 combined. $2000=1400+$600 =1:2 and 2:4 ratio.

5 0
2 years ago
99 % of the trees in our neighborhood are eucalyptus trees. The town planning commission wants to get rid of some of these trees
Brut [27]

Answer:

50%

Step-by-step explanation:

Let the total number of trees be T and suppose that this is made up of eucalyptus trees E and other kinds of trees, O.

Then E+O=T, and since 99% of the trees are eucalyptus trees, EE+O=0.99.

Therefore

0.99E+0.99O=E

0.01E=0.99O

E=99O.

Suppose we reduce the number of eucalyptus trees by some amount x and that the remaining number of eucalyptus trees are now 98% of the total trees.

Then we would have E−x(E−x)+O=0.98.

Therefore,

0.02(E−x)=0.98O

0.02E−0.02x=0.98O

0.02x=0.02E−0.98O

x=E−50(0.98)O

x=E−49O

x=E−49(E99)

x=5099E≈0.505050...×E.

So we end up removing a little over half of the eucalyptus trees. EDIT: Forgot to mention - removing 50.505050...% of the eucalyptus trees means that we are removing 0.50505050....×0.99T which is 0.5T or half the trees in the neighborhood.

3 0
3 years ago
SAQ 5.1
iVinArrow [24]

Answer:

1. (i) 7, 21, 63, 189

(ii) 20, 10, 5, 2.5

2. (i) n²+n (where n = 1, 2, 3, ..)

(ii) 8/(10^n) (where n = 1, 2, 3, ..)

(iii) 1/(n+1) (where n = 1, 2, 3, ..)

4 0
3 years ago
Renee is simplifying the expression (7) (StartFraction 13 over 29 EndFraction) (StartFraction 1 over 7 EndFraction). She recogni
dsp73

Answer:

The correct option is commutative property.

Step-by-step explanation:

The expression that Renee is simplifying is:

(7)\cdot(\frac{13}{29})\cdot(\frac{1}{7})

It is provided that, Renee recognizes that 7 and \frac{1}{7} are reciprocals, so she would like to find their product before she multiplies by \frac{13}{29}.

The associative property of multiplication states that:

a\times b\times c=(a\times b)\times c=a\times (b\times c)

The commutative property of multiplication states that:

a\times b\times c=a\times c\times b=c\times a\times b

The distributive property of multiplication states that:

a\cdot (b+c)=a\cdot b+a\cdot c

The identity property of multiplication states that:

a\times 1=a\\b\times 1=b

So, Renee should use the commutative property of multiplication to find the product of 7 and \frac{1}{7},

(7)\cdot(\frac{13}{29})\cdot(\frac{1}{7})=(7\times\frac{1}{7})\times\frac{13}{29}=\frac{13}{29}

Thus, the correct option is commutative property.

5 0
3 years ago
Read 2 more answers
Which statement correctly describes this expression?<br> 2m^3 - 11
Nady [450]

Answer:

<h2>D</h2>

The cube of twice a number decreased by 11

6 0
2 years ago
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