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erastova [34]
4 years ago
10

How could you test whether 7 is a factor of 291

Mathematics
2 answers:
nekit [7.7K]4 years ago
4 0

All you need to do is divide 291 by 7. If the quotient is a whole number, then 7 would be a factor of 291.


Let's test it out then, look at the picture attached.


As you can see in the picture attached, there is a remainder, so this would mean that 7 is not a factor of 291.

snow_tiger [21]4 years ago
4 0
 <span>Divide 291 by 7. If it is a whole number it is a factor. If not, it isn't. In this case 291 divided by 7 = 41.571428 so it is not a factor.</span>
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Since the divisor is in the form of <em>x - c</em>, use what is called Synthetic Division. Remember, in this formula, -c gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:

2| -2 1 5 0 4 1

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-2 -3 -1 -2 0 1→ -2x⁴ - 3x³ - x² -2x + [x - 2]⁻¹

You start by placing the <em>c</em> in the top left corner, then list all the coefficients of your dividend [-2x⁵ + x⁴ + 5x³ + 4x + 1]. You bring down the original term closest to <em>c</em> then begin your multiplication. Now depending on what symbol your result is, tells you whether the next step is to <em>subtract</em> or <em>add</em>, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that -2 in your quotient can be a -2x⁴, and the -3 [x³] follows right behind it, then 1 [-x²], -2[x], and finally, [1\x - 2] (remainder is 1, so set it over your denominator, which is the divisor), giving you the other factor of -2x⁴ - 3x³ - x² -2x + [x - 2]⁻¹.

I am joyous to assist you anytime.

**(x - 2)^{-1} =  \frac{1}{x - 2}

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3 years ago
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An alternative way of graphing

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