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klemol [59]
4 years ago
14

Is 0.062 equal to .062

Mathematics
2 answers:
vitfil [10]4 years ago
7 0
Yes they are equal numbers. You can write them either way because in “.062” you just skip and don’t write a “0” in front.
Alona [7]4 years ago
4 0
 yes. The zero to the left of the decimal point does not affect the overall value of the problem when removed, since it is zero.
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Step-by-step explanation:

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The diagonal of a rectangle is 25 in. The width is 15 in. What is the area of the rectangle
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Three coins are tossed. Let the event H = all Heads and the event K = at least one Heads. (match like 1-a, etc)
Aleksandr [31]

Given:

Three coins are tossed.

Let the event H represents all Heads and the event K represents at least one Heads.

To find:

a. The probability that the outcome is all heads if at least one coin shows a heads.

b. P(K) = ?

c. P(H∩K) = ?

Solution:

If three coins are tossed, then the total possible outcomes are:

{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

Total outcomes = 8

Possible outcomes for all Heads = 1

Possible outcomes for at least one Heads = 7

Let the following events:

H = all Heads

K = at least one Heads.

Then,

H=\{HHH\}

K=\{HHH, HHT, HTH, HTT, THH, THT, TTH\}

H\cap K=\{HHH\}

Now,

P(K)=\dfrac{7}{8}

P(H\cap K)=\dfrac{1}{8}

a. The probability that the outcome is all heads if at least one coin shows a heads is:

P(H|K)=\dfrac{P(H\cap K)}{P(K)}

P(H|K)=\dfrac{\dfrac{1}{8}}{\dfrac{7}{8}}

P(H|K)=\dfrac{1}{7}

Therefore, the probability that the outcome is all heads if at least one coin shows a heads is \dfrac{1}{7}.

b. P(K)=\dfrac{7}{8}

c. P(H\cap K)=\dfrac{1}{8}

8 0
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