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LekaFEV [45]
2 years ago
15

Rewrite the following fractions as division problems. a. 7⁄11 b. 5⁄2 c. 9⁄10 d. 7⁄15

Mathematics
1 answer:
larisa [96]2 years ago
3 0
A. 7/11= 7 ÷ 11
B. 5/2= 5 ÷ 2
C. 9/10= 9 ÷ 10
D. 7/15= 7 ÷ 15

A fraction is just a division problem. 7/11 would be considered 7 ÷ 11 (or just 7/11) just do the same for the rest of the fractions.
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The 2 ft side length of the scale drawing corresponds to a side length of 120 feet for the actual skate park. What is the scale
SOVA2 [1]

Answer:

The scale factor is \frac{1}{60}

Step-by-step explanation:

we know that

The scale factor is equal to the ratio between the side length of the scale drawing to the corresponding side length in the actual

so

\frac{2}{120}=\frac{1}{60}

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3 years ago
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Double bubble/ triple 100 points !!!!!!
balu736 [363]

Answer:

see below

Step-by-step explanation:

We need to find the diameter of the square

We can find this using the Pythagorean theorem

a^2+b^2 = c^2  where the legs are 7 and 7 and the diameter is c

7^2 +7^2 = c^2

49+49 = c^2

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sqrt(98) = sqrt(c^2)

9.899494937 = c

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3 years ago
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I NEED HELP :_( Which of the following points is in the solution set of y > -x∧2 + 5? (0, 5) (2, 4) (1, 3)
marysya [2.9K]

Answer:

\huge\boxed{(2;\ 4)}

Step-by-step explanation:

We have

y>-x^2+5

Put the coordinates of the given points and check the inequality:

For (0; 5) → x = 0; y = 5

5>-0^2+5\\5>0+5\\5>5\qquad\bold{FALSE}

For (2; 4) → x = 2, y = 4

4>-2^2+5\\4>-4+5\\4>1\qquad\bold{TRUE}

For (1; 3) → x = 1, y = 3

3>1^2+5\\3>1+5\\3>6\qquad\bold{FALSE}

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3 years ago
A multiplication problem is shown 789 times what equals 8679 what the missing number
navik [9.2K]

Answer:

789

Step-by-step explanation:

8679/789 = 11

5 0
3 years ago
Need help! Does anyone know how to do this type of math? (It's geometry)
mart [117]

Answer:

71

Step-by-step explanation:

<u>refer</u><u> </u><u>the</u><u> attachment</u>

to solve the question we need to recall one of the most important theorem of circle known as two tangent theorem which states that <u>tangents </u><u>which</u><u> </u><u>meet </u><u>at</u><u> the</u><u> </u><u>same</u><u> </u><u>point</u><u> </u><u>are </u><u>equal</u><u> </u><u> </u>that is being said

  • FA=AI=17
  • CH=CG=2.5

since \rm BA=FA+FB and it's given that FA and BA are 17 and 29 FB should be

  • \rm 29=17+FB

therefore,

  • FB=29-17=\boxed{12}

once again by two tangent theorem we acquire:

  • FB=BH=\boxed{12}

As BC=BH+CH,BC is

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likewise,AD=AI+DI so,

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thus,

  • DI=21-17=\boxed{4}

By the theorem we obtain:

  • DI=DG=4

Similarly,DC=DG+CH therefore,

  • DC=4+2.5=\boxed{6.5}

Now <u>finding</u><u> </u><u>the</u><u> </u><u>Perimeter</u><u> </u><u>of </u><u>ABCD</u>

  • P_{\text{ABCD}}=\text{AB+AD+BC+DC}

substitute what we have and got

  • P_{\text{ABCD}}=\text{29+21+14.5+6.5}

simplify addition:

  • P_{\text{ABCD}}=\boxed{71}

hence,

the Perimeter of ABCD is <u>7</u><u>1</u>

4 0
2 years ago
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