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2 years ago

Plsssssss help me with thiss.

Mathematics

1 answer:

Oksanka [162]2 years ago

7 0

Answer:

Step-by-step explanation:

you need to mutpliy all or your numders 17 x 4 x 8 x 9 = 4896m

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Figure ABCD is similar to figure MNKL. Write a proportion that contains BC and KL.

joja [24]

B/C = K/L because they are similar

7 0

3 years ago

Olivia ordered 24 cupcakes and a layer of cake. The layer cost $16 and the total cost of the order was $52. What was the price o

ArbitrLikvidat [17]

$16 was only for the layer.
$52-$16= cost of the cupcakes in total.
$36=cost of all cupcakes
36/24= cost of one cupcake
1.5= cost of one cupcake

each cupcake costs $1.50

4 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B10%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7B5%7D%20" id="TexFormula1" title=" \fr

Nimfa-mama [501]

You may solve this ratio by cross multiplying. To do this, you multiply the numbers diagonally across from each other.

x/10 = 1/5
10(1) = x(5)
10 = 5x
2 = x

Answer:
x = 2

4 0

3 years ago

3. Let U and V be subspaces of a vector space W. Prove that their intersection UnV is also a subspace of W

kenny6666 [7]

Answer: The proof is done below.

Step-by-step explanation: Given that U and V are subspaces of a vector space W.

We are to prove that the intersection U ∩ V is also a subspace of W.

(a) Since U and V are subspaces of the vector space W, so we must have

0 ∈ U and 0 ∈ V.

Then, 0 ∈ U ∩ V.

That is, zero vector is in the intersection of U and V.

(b) Now, let x, y ∈ U ∩ V.

This implies that x ∈ U, x ∈ V, y ∈ U and y ∈ V.

Since U and V are subspaces of U and V, so we get

x + y ∈ U and x + y ∈ V.

This implies that x + y ∈ U ∩ V.

(c) Also, for a ∈ R (a real number), we have

ax ∈ U and ax ∈ V (since U and V are subspaces of W).

So, ax ∈ U∩ V.

Therefore, 0 ∈ U ∩ V and for x, y ∈ U ∩ V, a ∈ R, we have

x + y and ax ∈ U ∩ V.

Thus, U ∩ V is also a subspace of W.

Hence proved.

7 0

3 years ago

An ideal gas is confined within a closed cylinder at a pressure of 2.026 × 105 Pa by a piston. The piston moves until the volume

Elis [28]

Answer:

The final pressure of the gas when its temperature returns to its initial value $1.8234\times 10^6$ Pa.

Step-by-step explanation:

Given : An ideal gas is confined within a closed cylinder at a pressure of $2.026\times 10^5$ Pa by a piston. The piston moves until the volume of the gas is reduced to one-ninth of the initial volume.